python 简单的构造树结构_python xtree

展示：

def xtree(data):
    list = []
    dict = {}
    if data:
        for i in data:
            dict[i['id']] = i

        for j in data:
            if j['pid'] == 0:
                list.append(j)
            else:
                if 'son' not in dict[j['pid']]:
                    dict[j['pid']]['son'] = []
                dict[j['pid']]['son'].append(j)
        return list

删除：

async def delpermission(ns):
    db = DBPools()
    async with db.sqlorContext('kboss') as sor:
        if ns:
            ns['del_flg'] = '1'
            await sor.U('permission', ns)
            dictns = {'parentid': ns['id']}
            reacs = await sor.R('permission', dictns)
            for i in reacs:
                await delpermission({'id':i['id']})
            return {'status': True, 'msg': '删除成功'}
    return {'status': False, 'msg': '删除失败'}