封装python函数判断成绩等级_python判断成绩等级思路与实现

方法一：使用正则表达式

import re

while True:

score = (input("请输入成绩:"))

if score.isdigit():

score = int(score)

elif (re.match('^\d+\.\d+$',score)):

score = float(score)

else:

if score.lower()=='q':

break

else:

print("请输入0到100数字")

continue

if 0<=score<=100:

if 90<=score<=100:

print("A")

elif 80<=score<90:

print("B")

elif 60<=score<80:

print("C")

elif 0<=score<60:

print("D")

else:

print("输入有误")

continue

二、使用isdigit（）判断是否为整数实现

while True:

score = (input("请输入成绩:"))

if len(str(score))<=5:

if score.lower() == 'q':

break

elif score=='':

continue

_score=score.replace('.','',1)

if _score.isdigit():

if _score == score:

score = int(score)

else:

score = float(score)

if 90<=score<=100:

print("A")

elif 80<=score<90:

print("B")

elif 60<=score<80:

print("C")

elif 0<=score<60:

print("D")

else:

print("输入有误")

continue

else:

print("请输入0到100数字，小数点最多2位")

continue

方式三：使用异常处理

def Score():

while True:

score = (input("请输入成绩:"))

if score.lower() == 'q':

break

try:

score = float(score)

if 90<=score<=100:

print("A")

elif 80<=score<90:

print("B")

elif 60<=score<80:

print("C")

elif 0<=score<60:

print("D")

else:

print('请输入0到100之间')

except ValueError as e:

print('输入有误，错误信息为:%s'%e)