解决报错SyntaxError：Unexpected end of JSON input_syntaxerror: unexpected end of json input

跳转页面传递参数

var selectWorker = JSON.stringify(selectWorker);
uni.navigateTo({
    url: '../recordForm/recordForm?selectWorker=' + selectWorker
})

onLoad(option) {
	console.log(option)
	var _this = this;
 
	// 选中的工人
	var selectWorker = JSON.parse(option.selectWorker);
	var workerIdsArray = [];
	for (var i = 0; i < selectWorker.length; i++) {
		workerIdsArray.push(selectWorker[i].id);
	}
	var workerIds = workerIdsArray.join(',');
	console.log(workerIds);
	_this.selectWorker = selectWorker;
	_this.workerIds = workerIds;
},

报错提示SyntaxError：Unexpected end of JSON input

 解决方案

原因：若对象的参数或数组的元素中遇到地址中包括?& - _ . ! ~ * ' ( )等特殊符号时，对象/数组先要通过JSON.stringify转化为字符串再通过encodeURIComponent编码，接收时，先通过decodeURIComponent解码再通过JSON.parse转换为JSON格式的对象/数组。

修改如下：

var selectWorker = JSON.stringify(selectWorker);
uni.navigateTo({
    url: '../recordForm/recordForm?selectWorker=' + encodeURIComponent(selectWorker)
})

onLoad(option) {
	console.log(option)
	var _this = this;
 
	// 选中的工人
	var selectWorker = JSON.parse(decodeURIComponent(option.selectWorker));
	var workerIdsArray = [];
	for (var i = 0; i < selectWorker.length; i++) {
		workerIdsArray.push(selectWorker[i].id);
	}
	var workerIds = workerIdsArray.join(',');
	console.log(workerIds);
	_this.selectWorker = selectWorker;
	_this.workerIds = workerIds;
},