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分析
class Solution { public: int deleteAndEarn(vector<int>& nums) { const int N = 10001; // 预处理 int arr[N] = {0}; for (int& e : nums) arr[e] += e; // 在 arr 上进行 打家劫舍 问题 vector<int> f(N), g(N); // 填表 for(int i = 1; i < N; i++) { f[i] = g[i - 1] + arr[i]; g[i] = max(f[i - 1], g[i - 1]); } return max(f[N - 1], g[N - 1]); } };
分析:
class Solution {
public:
int minCost(vector<vector<int>>& costs) {
const int N = costs.size() + 1;
vector<int> dp0(N), dp1(N), dp2(N);
for (int i = 1; i < N; i++) {
dp0[i] = costs[i - 1][0] + min(dp1[i - 1], dp2[i - 1]);
dp1[i] = costs[i - 1][1] + min(dp0[i - 1], dp2[i - 1]);
dp2[i] = costs[i - 1][2] + min(dp1[i - 1], dp0[i - 1]);
}
return min(dp0[N - 1], min(dp1[N - 1], dp2[N - 1]));
}
};
class Solution {
public:
int minCost(vector<vector<int>>& costs) {
const int N = costs.size() + 1;
vector<vector<int>> dp(N, vector<int>(3, 0));
for (int i = 1; i < N; i++) {
dp[i][0] = costs[i - 1][0] + min(dp[i - 1][1], dp[i - 1][2]);
dp[i][1] = costs[i - 1][1] + min(dp[i - 1][0], dp[i - 1][2]);
dp[i][2] = costs[i - 1][2] + min(dp[i - 1][1], dp[i - 1][0]);
}
return min(dp[N - 1][0], min(dp[N - 1][1], dp[N - 1][2]));
}
};
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