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示例对象
private Integer id;
private String name;
private BigDecimal money;
private Integer num;
public Apple(Integer id, String name, BigDecimal money, Integer num) {
this.id = id;
this.name = name;
this.money = money;
this.num = num;
}
数据
List<Apple> appleList = new ArrayList<>();//存放apple对象集合
Apple apple1 = new Apple(1,"苹果1",new BigDecimal("3.25"),10);
Apple apple12 = new Apple(1,"苹果2",new BigDecimal("1.35"),20);
Apple apple2 = new Apple(2,"香蕉",new BigDecimal("2.89"),30);
Apple apple3 = new Apple(3,"荔枝",new BigDecimal("9.99"),40);
appleList.add(apple1);
appleList.add(apple12);
appleList.add(apple2);
appleList.add(apple3);
1、分组
List里面的对象元素,以某个属性来分组,例如,以id分组,将id相同的放在一起:
//List 以ID分组 Map<Integer,List<Apple>>
Map<Integer, List<Apple>> groupBy = appleList.stream().collect(Collectors.groupingBy(Apple::getId));
System.err.println("groupBy:"+groupBy);
{1=[Apple{id=1, name='苹果1', money=3.25, num=10}, Apple{id=1, name='苹果2', money=1.35, num=20}], 2=[Apple{id=2, name='香蕉', money=2.89, num=30}], 3=[Apple{id=3, name='荔枝', money=9.99, num=40}]}
List<User> users = new LinkedList<>();
users.add(new User("Jim", 12));
users.add(new User("John", 18));
users.add(new User("Tom", 21));
users.add(new User("Leo", 30));
users.add(new User("Kate", 44));
users.add(new User("Lio", 50));
Map<String, List<User>> tripleUsers = users.stream()
.collect(Collectors.groupingBy((Function<User, String>) user -> {
String key;
if (user.getAge() <= 20) {
key = "less20";
} else if (user.getAge() <= 40) {
key = "less40";
} else {
key = "more40";
}
return key;
}, Collectors.toList()));
System.out.println(tripleUsers);
2、List转Map
id为key,apple对象为value
/**
* List -> Map
* 需要注意的是:
* toMap 如果集合对象有重复的key,会报错Duplicate key .... 解决办法见我的另一篇文章。。。
* apple1,apple12的id都为1。
* 可以用 (k1,k2)->k1 来设置,如果有重复的key,则保留key1,舍弃key2
*/
Map<Integer, Apple> appleMap = appleList.stream().collect(Collectors.toMap(Apple::getId, a -> a,(k1,k2)->k1));
{1=Apple{id=1, name='苹果1', money=3.25, num=10}, 2=Apple{id=2, name='香蕉', money=2.89, num=30}, 3=Apple{id=3, name='荔枝', money=9.99, num=40}}
3、过滤Filter
从集合中过滤出来符合条件的元素:
//过滤出符合条件的数据
示例一:
List<Apple> filterList = appleList.stream().filter(a -> a.getName().equals("香蕉")).collect(Collectors.toList());
System.err.println("filterList:"+filterList);
[Apple{id=2, name='香蕉', money=2.89, num=30}]
示例二:
List<user> filterAges = users.stream().filter(user->ages.contains(user.getAge())).collect(Collectors.toList());
以下代码就相当于一个foreach
filterAges.stream().forEach(user -> {
System.out.println(user.getName()+"======"+user.getEmail());
});
多条件过滤
List<user> filter= users.stream()
.filter(user -> user.getName().indexOf("月") > -1 || user.getEmail().indexOf("mu") > -1)
.collect(Collectors.toList());
collect.stream().forEach(user -> {
System.out.println(user.getName()+"======"+user.getEmail());
});
4、求和
将集合中的数据按照某个属性求和
//计算 总金额
BigDecimal totalMoney = appleList.stream().map(Apple::getMoney).reduce(BigDecimal.ZERO, BigDecimal::add);
System.err.println("totalMoney:"+totalMoney); //totalMoney:17.48
5、查找流中最大 最小值
Collectors.maxBy 和 Collectors.minBy 来计算流中的最大或最小值。
Optional<Dish> maxDish = Dish.menu.stream().
collect(Collectors.maxBy(Comparator.comparing(Dish::getCalories)));
maxDish.ifPresent(System.out::println);
Optional<Dish> minDish = Dish.menu.stream().
collect(Collectors.minBy(Comparator.comparing(Dish::getCalories)));
minDish.ifPresent(System.out::println);
6、去重
Java8 lambda自带的去重为 distinct 方法, 但是只能过滤整体对象和基本数据类型, 不能实现对象里的某个值进行判定去重, 比如:
List<Integer> numbers = Arrays.asList(8, 2, 8, 2, 6, 5, 9, 5, 6, 7);
List<Integer> distinctNumbers = numbers.stream()
.distinct()
.collect(Collectors.toList());
System.out.println(distinctNumbers);
如果对一个实体对象List , 对指定的Student的某个字段作为条件去重就不行了,例如name字段,以下代码达不到效果
List<Student> distinctUsers = users.stream()
.distinct(Student::getName)
.collect(Collectors.toList());
可以通过一下代码实现根据实体类的字段去重
import static java.util.Comparator.comparingLong;
import static java.util.stream.Collectors.collectingAndThen;
import static java.util.stream.Collectors.toCollection;
// 根据id去重
List<Person> unique = appleList.stream().collect(
collectingAndThen(
toCollection(() -> new TreeSet<>(comparingLong(Apple::getId))), ArrayList::new)
);
根据多个字段去除重复
List<User> userList = users.stream() .collect(
Collectors.collectingAndThen(
Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(user -> user.getName()+";"+user.getId()))), ArrayList::new));
List去重两个相同的实体类对象或者相同的单个对象字段
List<String> classNameList = new ArrayList(new HashSet(userList));
7、获取实体类对象中某一个字段转为List
List<Long> userIds = users.stream().map(User::getId).collect(Collectors.toList());
User::getId 就相当于 a —> a.getId()
8、排序
可通过Sort对单字段多字段排序
//单字段排序,根据id排序
userList.sort(Comparator.comparing(User::getId));
//多字段排序,根据id,年龄排序
userList.sort(Comparator.comparing(User::getId).thenComparing(User::getAge));
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