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python中一元二次方程的解,用python做一元二次方程_python编写函数求一元二次方程的解
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大家好，小编为大家解答python求解一元二次方程的解的问题。很多人还不知道python一元二次方程求解代码，现在让我们一起来看看吧！
一元二次方程的解法有以下几种：公式法、因式分解法、配方法、求根公式法。
下面是使用Python代码实现一元二次方程的解法：
1. 公式法：
```python
import math
def solve_quadratic_equation(a, b, c):
delta = b**2 - 4*a*c
if delta < 0:
return "无实根"
elif delta == 0:
x = -b / (2*a)
return x
else:
x1 = (-b + math.sqrt(delta)) / (2*a)
x2 = (-b - math.sqrt(delta)) / (2*a)
return x1, x2
# 示例
a = 1
b = -3
c = 2
result = solve_quadratic_equation(a, b, c)
print(result)
```
2. 因式分解法：
```python
def solve_quadratic_equation(a, b, c):
if a == 0:
return "不是二次方程"
if b == 0:
x = 0
if -c/a >= 0:
return x, math.sqrt(-c/a)
else:
return "无实根"
if c == 0:
x1 = 0
x2 = -b/a
return x1, x2
delta = b**2 - 4*a*c
if delta < 0:
return "无实根"
elif delta == 0:
x = -b / (2*a)
return x
else:
x1 = (-b + math.sqrt(delta)) / (2*a)
x2 = (-b - math.sqrt(delta)) / (2*a)
return x1, x2
# 示例
a = 1
b = -3
c = 2
result = solve_quadratic_equation(a, b, c)
print(result)
```
3. 配方法：
```python
def solve_quadratic_equation(a, b, c):
if a == 0:
return "不是二次方程"
if b == 0:
x = 0
if -c/a >= 0:
return x, math.sqrt(-c/a)
else:
return "无实根"
if c == 0:
x1 = 0
x2 = -b/a
return x1, x2
delta = b**2 - 4*a*c
if delta < 0:
return "无实根"
elif delta == 0:
x = -b / (2*a)
return x
else:
x1 = (-b + math.sqrt(delta)) / (2*a)
x2 = (-b - math.sqrt(delta)) / (2*a)
return x1, x2
# 示例
a = 1
b = -3
c = 2
result = solve_quadratic_equation(a, b, c)
print(result)
```
4. 求根公式法：
```python
def solve_quadratic_equation(a, b, c):
if a == 0:
return "不是二次方程"
if b == 0:
x = 0
if -c/a >= 0:
return x, math.sqrt(-c/a)
else:
return "无实根"
if c == 0:
x1 = 0
x2 = -b/a
return x1, x2
delta = b**2 - 4*a*c
if delta < 0:
return "无实根"
elif delta == 0:
x = -b / (2*a)
return x
else:
x1 = (-b + math.sqrt(delta)) / (2*a)
x2 = (-b - math.sqrt(delta)) / (2*a)
return x1, x2
# 示例
a = 1
b = -3
c = 2
result = solve_quadratic_equation(a, b, c)
print(result)
```
以上是四种常见的一元二次方程解法的Python代码实现python流星雨特效代码简单。根据输入的系数a、b、c，可以得到方程的解或者无解的提示。
