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题目:
将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例 1:
输入:l1 = [1,2,4], l2 = [1,3,4]
输出:[1,1,2,3,4,4]
示例 2:
输入:l1 = [], l2 = []
输出:[]
示例 3:
输入:l1 = [], l2 = [0]
输出:[0]
code:
# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]: if not list1 : return list2 elif not list2: return list1 res = ListNode() ans = res while list1 != None and list2 != None: if list1.val <= list2.val: ans.next = list1 list1 = list1.next else: ans.next = list2 list2 = list2.next ans = ans.next if list1 == None: ans.next = list2 else: ans.next = list1 return res.next
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