数组与矩阵：不包含本位置值的累乘数组（C++）_未包含的矩阵c++

//★题目：不包含本位置值的累乘数组
//要求：给定一个整型数组arr，返回不包含本位置值的累乘数组。
//      时间复杂度O(N)；除需要返回的结果数组外，空间复杂度O(1)
//      例如：arr = [2,3,1,4]，返回[12,8,24,6]。除自己外，其他位置上累乘
//分析：主要考虑数组中零元素的个数
#include <iostream>
#include <vector>

using namespace std;

vector<int> multiplication(vector<int> matrix);
void printVector1(vector<int> matrix);
vector<int> generateDesignated1Vector(int *arr, int size);

int main()
{
	int arrayMine[4] = { 2, 3, 1, 4 };
	int *arr = arrayMine;
	vector<int> matrix = generateDesignated1Vector(arr, 4);
	printVector1(matrix);
	cout << endl;
	vector<int> result = multiplication(matrix);
	printVector1(result);

	system("pause");
	return 0;
}

vector<int> multiplication(vector<int> matrix)
{
	int multiplication = 1;
	int numZero = 0;
	int indexZero = 0;
	vector<int> result;
	result = matrix;
	if (matrix.size()<2)
	{
		return matrix;
	}
	for (int i = 0; i < matrix.size(); i++)
	{
		if (matrix[i]==0)
		{
			numZero++;
			indexZero = i;
		}
		else
		{
			multiplication *= matrix[i];
		}
	}
	if (numZero == 0)
	{
		for (int i = 0; i < matrix.size(); i++)
		{
			result[i] = multiplication / matrix[i];
		}
	}
	else if (numZero == 1)
	{
		for (int i = 0; i < matrix.size(); i++)
		{
			if (i==indexZero)
			{
				result[i] = multiplication;
			}
			else
			{
				result[i] = multiplication / matrix[i];
			}
		}
	}
	else if (numZero == 2)
	{
		for (int i = 0; i < matrix.size(); i++)
		{
			result[i] = 0;
		}
	}
	return result;
}

void printVector1(vector<int> matrix)
{
	int size = matrix.size();
	for (int i = 0; i < size; i++)
	{
		cout << matrix[i] << " ";
	}
}

vector<int> generateDesignated1Vector(int *arr, int size)
{
	int setNum = 0;
	int arrIndex = 0;
	vector<int> result;
	if (size == 0)
	{
		return result;
	}
	static int vecIndex = 0;
	while (vecIndex < size)
	{
		setNum = arr[arrIndex];
		arrIndex++;
		result.push_back(setNum);
		vecIndex++;
	}
	return result;
}
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