python 转置_python转置

zip()实现list转置

>>> a = [[1,2,3], [4,5,6], [7, 8, 9], [10, 11, 12]]
>>> a = list(map(list, zip(*a)))

输出：
[[1, 4, 7, 10], [2, 5, 8, 11], [3, 6, 9, 12]]
1
2
3
4
5

使用 numpy ---- 数据类型可能改变

np.stack()

>>> a = [[1,2,3], [4,5,6], [7, 8, 9], [10, 11, 12]]
>>> np.stack((a),axis=1)
输出：
array([[ 1,  4,  7, 10],
       [ 2,  5,  8, 11],
       [ 3,  6,  9, 12]])
1
2
3
4
5
6

np.transpose()

>>> a = [[1,2,3], [4,5,6], [7, 8, 9], [10, 11, 12]]
>>> np.transpose(a)
array([[ 1,  4,  7, 10],
       [ 2,  5,  8, 11],
       [ 3,  6,  9, 12]])
1
2
3
4
5

.T

>>> A = np.mat([[1,2,3],[4,5,6],[7,8,9]])
>>> A.T
>>> A.swapaxes(0, 1)
matrix([[1, 4, 7],
        [2, 5, 8],
        [3, 6, 9]])
1
2
3
4
5
6

使用python列表表达式

>>> A = [[1,2,3],[4,5,6],[7,8,9]]
>>> B = [[A[j][i] for j in range(len(A))] for i in range(len(A[0]))]
>>> B
[[1, 4, 7], [2, 5, 8], [3, 6, 9]]
1
2
3
4