ExtJS实现同步请求_ext.lib.ajax.getconnectionobject().conn

作者：weixin_40725706 | 2024-03-27 06:02:33

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ext.lib.ajax.getconnectionobject().conn

同步方式请求：

必须引入ext-basex.js文件

 
  var conn = Ext.lib.Ajax.getConnectionObject().conn; conn.open("GET", 'your url',false); conn.send(null); alert(conn.responseText); 

或者

var conn = Ext.lib.Ajax.getConnectionObject().conn;
conn.open("POST", url, false);
conn.send("发送到服务器端的信息");
data = conn.responseText;
alert(data);

关键是要设置false这个参数

异步方式请求：

 
  Ext.Ajax.request({                         url : 'listpublishersms.action',                         success : function(response, options) {                             var temp = "<chart caption='"                             + startField.getValue().dateFormat("Y-m-d")                             + "至"                             + endField.getValue().dateFormat("Y-m-d")                             + "' baseFontSize='12' formatNumberScale='0' showBorder='1'>";                              var responseArray = Ext.util.JSON                                     .decode(response.responseText);                             alert(responseArray.list.length);                             for (var i = 0;i < responseArray.list.length ;i++) {                                        var pname = responseArray.list[i].pname;                                         var count = responseArray.list[i].count;                                         temp += "<set label='" + pname                                             + "' value='" + count + "'/>";                               }                             temp += "</chart>";                              chart_chart.setDataXML(temp);                         }                     });  

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