赞
踩
看到Beep()就会想起上世纪90年代初在8086的机器或者稍后的286、386机器上用解释型Basic编简谱玩的情景,这便是那个声霸卡还没上市的年代里,几乎是人们在PC上唯一可编的声音了。
Beep的函数原型:
BOOL Beep(
DWORD dwFreq; /*指定要发出的频率(HZ)*/
DWORD dwDuration; /*指定发音的时长,以毫秒为单位*/
);
通常先把do re mi ...的频率预定义好,再照着简谱把频率和时长编入两个数组或一个结构体数组。
#define do 523
#define re 578
#define mi 659
#define fa 698
#define so 784
#define la 880
#define si 988
......
int freq[] = { do,re,mi,do,do,re,mi,do,...}
int duration[] = {300,300,300,300,300,300,300,300,...}
最后用Beep()循环输出。
对此我做了些小改进:把频率定入一个结构体数组便于反复调用;简谱放入一个vector容器就不用管谱子的长短不用管数组的下标,只要按顺序push_back()每一个音符,还能随时插入删除某个音符,重复的小节可以用循环多次输出以缩短代码长度;简谱转代码时“所见即所得”看到什么数字就写入什么数字;音符的时长也以“拍”为单位,每个小节后加个空行便于检查每节的总时长。源代码如下:
- #include <array>
- #include <vector>
- #include <iostream>
- #include <windows.h>
-
- using namespace std;
-
- #define PAI 300 //一拍的时长,可以自行调整
-
- struct tone{
- short a; short d; short g; //中音;低音;高音
- short b; short e; short f; //半阶音
- };
-
- struct tune{
- short t; //唱名
- float l; //音长
- short b; //音调
- };
-
- array<tone,8>m;
-
- short t(short a,short b)
- {
- switch(b){
- case 0: return m[a].a;
- case 1: return m[a].d;
- case 2: return m[a].g;
- case 3: return m[a].b;
- case 4: return m[a].e;
- case 5: return m[a].f;
- }
- }
-
- short p(float p)
- {
- return (short)(PAI*p);
- }
-
- void initTone(void)
- { //把各音符的频率写入数组,一劳永逸可以随时调用
- m.at(0)={0,0,0,0,0,0};
- m.at(1)={523,262,1046,554,277,1109};
- m.at(2)={578,294,1175,622,311,1245};
- m.at(3)={659,330,1318,659,330,1318};
- m.at(4)={698,349,1493,740,370,1556};
- m.at(5)={784,392,1568,831,415,1661};
- m.at(6)={880,440,1760,932,466,1865};
- m.at(7)={988,494,1976,988,494,1976};
- }
-
- void initTune(vector<tune>&s)
- {
- for (int i=0;i<2;i++){
- s.push_back({1,1,0});
- s.push_back({2,1,0});
- s.push_back({3,1,0});
- s.push_back({1,1,0});
- }
-
- for (int i=0;i<2;i++){
- s.push_back({3,1,0});
- s.push_back({4,1,0});
- s.push_back({5,2,0});
- }
-
- for (int i=0;i<2;i++){
- s.push_back({5,0.75,0});
- s.push_back({6,0.25,0});
- s.push_back({5,0.75,0});
- s.push_back({4,0.25,0});
- s.push_back({3,1,0});
- s.push_back({1,1,0});
- }
-
- for (int i=0;i<2;i++){
- s.push_back({1,1,0});
- s.push_back({5,1,1});
- s.push_back({1,2,0});
- }
-
- //以上根据简谱上的拍子和音调编入容器,方法如下:
- //第一个参数 1~7 对应do re mi fa so la si 0=休止符
- //第二个参数 1拍=1;半拍=0.5 四分之一拍=0.25 以此类推
- //第三个参数 一般就为0,低音=1 高音=2 对应的半阶音=3 4 5
- //转简谱时看到什么数字就是什么,不用记频率数方便编辑和排错
- }
-
- int main()
- {
- vector<tune>music;
- initTone();
- initTune(music);
-
- cout<<"开始演奏《两只老虎》"<<endl;
- for (auto m:music) Beep(t(m.t,m.b),p(m.l));
-
- return 0;
- }
一个程序独占控制台CPU时间来演奏音乐,没有一点实用性。我们再来编一首《送别》并实现“后台演奏”,注意:碰到简谱中有重复的小节可多放几个子函数以供多次调用。
实际上,演奏的同时还要做其他工作,就是要创建多个线程来完成几个不同的工作:先调用<pthread.h>库函数pthread_create()创建一个线程来播放背景音乐,然后让主程序开始做其它工作,并且可以按需要来选择哪项任务先结束。源代码如下:
- #include <array>
- #include <vector>
- #include <iostream>
- #include <ctime>
- #include <sstream>
- #include <windows.h>
- #include <pthread.h>
-
- using namespace std;
-
- #define PAI 400 //一拍的时长,可以自行调整
-
- struct tone{
- short a; short d; short g; //中音;低音;高音
- short b; short e; short f; //半阶音
- };
-
- struct tune{
- short t; //唱名
- float l; //音长
- short b; //音调
- };
-
- array<tone,8>m;
-
- short t(short a,short b)
- {
- switch(b){
- case 0: return m[a].a;
- case 1: return m[a].d;
- case 2: return m[a].g;
- case 3: return m[a].b;
- case 4: return m[a].e;
- case 5: return m[a].f;
- }
- }
-
- short p(float p)
- {
- return (short)(PAI*p);
- }
-
- void initTone(void)
- {
- m.at(0)={0,0,0,0,0,0};
- m.at(1)={523,262,1046,554,277,1109};
- m.at(2)={578,294,1175,622,311,1245};
- m.at(3)={659,330,1318,659,330,1318};
- m.at(4)={698,349,1493,740,370,1556};
- m.at(5)={784,392,1568,831,415,1661};
- m.at(6)={880,440,1760,932,466,1865};
- m.at(7)={988,494,1976,988,494,1976};
- }
-
- void repeat1(vector<tune>&s)
- {
- s.push_back({5,1,0});
- s.push_back({3,0.5,0});
- s.push_back({5,0.5,0});
- }
-
- void repeat2(vector<tune>&s)
- {
- s.push_back({6,1,0});
- s.push_back({1,1,2});
- s.push_back({5,2,0});
- }
-
- void repeat3(vector<tune>&s, short i)
- {
- s.push_back({i,2,0});
- s.push_back({0,1,0});
- s.push_back({0,1,0});
- }
-
- void initTune(vector<tune>&s)
- {
- for (int i=0;i<2;i++){
-
- repeat1(s);
- s.push_back({1,2,2});
- repeat2(s);
-
- s.push_back({5,1,0});
- s.push_back({1,0.5,0});
- s.push_back({2,0.5,0});
- s.push_back({3,1,0});
- s.push_back({2,0.5,0});
- s.push_back({1,0.5,0});
-
- repeat3(s,2);
-
- repeat1(s);
- s.push_back({1,1.5,2});
- s.push_back({7,0.5,0});
- repeat2(s);
-
- s.push_back({5,1,0});
- s.push_back({2,0.5,0});
- s.push_back({3,0.5,0});
- s.push_back({4,1.5,0});
- s.push_back({7,0.5,1});
-
- repeat3(s,1);
-
- s.push_back({6,1,0});
- s.push_back({1,1,2});
- s.push_back({1,2,2});
-
- s.push_back({7,0.5,0});
- s.push_back({6,0.5,0});
- s.push_back({7,0.5,0});
- s.push_back({1,2,2});
-
- s.push_back({6,0.5,0});
- s.push_back({7,0.5,0});
- s.push_back({1,0.5,2});
- s.push_back({6,0.5,0});
- s.push_back({6,0.5,0});
- s.push_back({5,0.5,0});
- s.push_back({3,0.5,0});
- s.push_back({1,0.5,0});
-
- repeat3(s,2);
-
- repeat1(s);
- s.push_back({1,1.5,2});
- s.push_back({7,0.5,0});
- repeat2(s);
-
- s.push_back({5,1,0});
- s.push_back({2,0.5,0});
- s.push_back({3,0.5,0});
- s.push_back({4,1.5,0});
- s.push_back({7,0.5,1});
-
- repeat3(s,1);
-
- }
- }
-
- void gotoXY(short x, short y)
- {
- COORD position = {x, y};
- HANDLE hConsole = GetStdHandle(STD_OUTPUT_HANDLE);
- SetConsoleCursorPosition(hConsole, position);
- }
-
- bool play_not_end=true; //设置演奏标记
-
- void* play(void* args)
- {
- vector<tune>music;
- initTone();
- initTune(music);
- gotoXY(28,8);
- cout<<"背景音乐:《送别》";
- for (auto v:music)
- if (play_not_end) Beep(t(v.t,v.b),p(v.l));
- else break;
-
- play_not_end=false;
- }
-
- char strTime[20];
-
- void* coutTime(void* args)
- {
- time_t lt;
- while (play_not_end){
- time(<);
- strftime(strTime,sizeof(strTime),"%Y-%m-%d %H:%M:%S",localtime(<));
- Sleep(300);
- }
- play_not_end=false;
- }
-
- int main()
- {
- pthread_t pt;
- int ret = pthread_create(&pt, NULL, play, NULL); //创建一个线程,play()变相成为背景音乐
- if (ret!=0) cout<<"create thread_1 error: error_code="<<ret<<endl;
-
- ret = pthread_create(&pt, NULL, coutTime, NULL); //再创建一个线程,用于显示当前系统时间
- if (ret!=0) cout<<"create thread_2 error: error_code="<<ret<<endl;
-
- //在 pthread_create()与 pthread_exit()之间,便是程序工作的主场
- Sleep(100);
- gotoXY(28,10);
- cout<<"工作开始:循环次数 ";
- for(int i=1;play_not_end;i++){
- gotoXY(48,10);
- cout<<i<<endl;
- gotoXY(60,0);
- cout<<strTime; //显示另外一个线程取回的时间
- Sleep(300);
- if (i==100) play_not_end=false; //工作在音乐演奏完之前结束,只要把标记设为false即可
- }
- gotoXY(28,12);
- cout<<"工作结束!"<<endl;
-
- pthread_exit(NULL);
- return 0;
- }
注意:本程序在Dev-C++ 5.11/编译器TDM-GCC 4.9.2 64-bit 上通过编译,若用VS编译找不到头文件<pthread.h>,请搜索“如何在vs2017上使用pthread.h”并自行安装库文件。
附:《两只老虎》、《送别》简谱
Copyright © 2003-2013 www.wpsshop.cn 版权所有,并保留所有权利。