【Python 函数和面向对象的实践应用】合肥工业大学python实验二题解_使用freqdict = eval(input()) 读入单词词频字典,再读入一段英文,默认按照英文

持续更新，新手代码勿喷.

题目：

第一题题解

n = int(input("请输入一个整数:"))
num = int(n*(n+1)/2)
j = 0
for i in range(65, 65+num):
    j += 1
    print(chr(i), end=" ")
    if j == n:
        print()
        n -= 1
        j = 0
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运行
运行

第二题题解：

m = str(input("输入m:"))
n = str(input("输入n:"))
n.lower()


def judge(m, n):
    flag = m.isalpha()
    if not flag:
        return "ERROR"
    else:
        m.lower()
    for i in m:
        if n.find(i) == -1:
            return "NOT FOUND"
    return "FOUND"

print(judge(m, n))
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第三题题解：

ID = str(input("请输入你的身份证号码："))
List1 = [0]*18
List2 = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
Dict = {0: '1', 1: '0', 2: 'X', 3: '9', 4: '8', 5: '7', 6: '6', 7: '5', 8: '4', 9: '3', 10: '2'}


def IsID(ID):
    for i in range(17):
        List1[i] = int(ID[i]) * List2[i]
    sum = 0
    for i in List1:
        sum += int(i)
    print(sum)
    print(sum%11)
    print(Dict.get(sum % 11))
    print(ID[17])
    if Dict.get(sum%11) == ID[17]:
        return "身份证号码检验为合法号码"
    else:
        return "身份证号码检验位错误"


print(IsID(ID))

# 220221197302296536
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第四题题解：

s = str(input("输入个人信息："))
new_s = s.split(" ")
for i in range(1, len(new_s)):
    if i == 1:
        print("姓名: {}".format(new_s[i]))
    elif i == 2:
        print("班级: {}".format(new_s[i]))
    elif i == 4:
        temp = str(new_s[4])
        temp = 2020 - int(temp[:4])
        print("年龄: {}岁".format(temp))
        
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运行
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第五题题解：

n = int(input("输入n:"))
s = ""
new_s = [None]*n
temp = ''
for i in range(n):
    s = str(input("输入第{}位同学信息：".format(i+1)))
    new_s[i] = s.split(" ")
for i in range(len(new_s)):
    for j in range(3):
        if j == 0:
            temp = str(new_s[i][j])
            temp = temp[:4] + "*******" + temp[11:]
        elif j == 1:
            temp = str(new_s[i][j])
            temp = temp[:1] + "*" + temp[2:]
        else:
            temp = str(new_s[i][j])
            temp = temp[:3] + "****" + temp[7:]
        new_s[i][j] = temp
print(new_s)
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第六题题解：

freqDict = eval(input("输入单词词频字典:"))
s = str(input("输入一段英文:"))
new_s = s.split(" ")
for i in new_s:
    if i in freqDict:
        freqDict[i] += 1
    else:
        freqDict[i] = 1
print(freqDict)
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