RestTemplate 401 获取错误信息处理_throw 401 exception

调用第三方api 若是服务返回状态码不为200，默认会执行DefaultResponseErrorHandler
异常处理

@Override
	public void handleError(ClientHttpResponse response) throws IOException {
		HttpStatus statusCode = getHttpStatusCode(response);
		switch (statusCode.series()) {
			case CLIENT_ERROR:
				throw new HttpClientErrorException(statusCode, response.getStatusText(),
						response.getHeaders(), getResponseBody(response), getCharset(response));
			case SERVER_ERROR:
				throw new HttpServerErrorException(statusCode, response.getStatusText(),
						response.getHeaders(), getResponseBody(response), getCharset(response));
			default:
				throw new RestClientException("Unknown status code [" + statusCode + "]");
		}
	}


	判断是否异常
	protected boolean hasError(HttpStatus statusCode) {
		return (statusCode.series() == HttpStatus.Series.CLIENT_ERROR ||
				statusCode.series() == HttpStatus.Series.SERVER_ERROR);
	}





	通常会直接已异常形势抛出，若不特殊处理无法获取返回提示信息。
	需要捕捉HttpClientErrorException 异常，则可获取返回信息

	try{
      ......
    }catch (HttpClientErrorException e) {
                String resBody = e.getResponseBodyAsString();
                log.info("客户端异常返回:{}", resBody);
                return new ResponseEntity<>(JSON.parseObject(resBody, res), e.getStatusCode());
            } 



            一开始我这样写，死活返回的都是null
            原来跟我设置的requestFactory有关，
            采用SimpleClientHttpRequestFactory 无法获取提示
             需要换成 HttpComponentsClientHttpRequestFactory
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