python class类里给列表排序_Python sorted对list和dict排序

sorted语法

sorted(iterable, key=None, reverse=False)

参数说明：

- iterable -- 可迭代对象。

- key --主要是用来进行比较的元素，只有一个参数，具体的函数的参数就是取自于可迭代对象中，指定可迭代对象中的一个元素来进行排序。

- reverse -- 排序规则，reverse = True 降序 ， reverse = False 升序(默认)。

返回：

- 一个新list对象

sorted对字典dict排序

①按键key排序

from operator import itemgetter

dict = {3: "B", 1: "A", 2: "C"}

# 按key升序 .items()取得3个(key,value)

# lambda x: x[0]取(key,value)的key 即(3,1,2)

d1 = sorted(dict.items(), key=lambda x: x[0], reverse=False) #

# 按key降序 itemgetter类似lambda

d2 = sorted(dict.items(), key=itemgetter(0), reverse=True) #

# 输出

print(d1, type(d1)) # [(1, "A"), (2, "C"), (3, "B")]

print(d2, type(d2)) # [(3, "B"), (2, "C"), (1, "A")]

[(1, ‘A"), (2, ‘C"), (3, ‘B")]

[(3, ‘B"), (2, ‘C"), (1, ‘A")]

②按值value排序

from operator import itemgetter

dict = {3: "B", 1: "A", 2: "C"}

# 按value升序 .items()取得3个(key,value)

# lambda x: x[1]取(key,value)的value 即("B","A","C")

d3 = sorted(dict.items(), key=lambda x: x[1], reverse=False) #

# 按value降序 itemgetter类似lambda

d4 = sorted(dict.items(), key=itemgetter(1), reverse=True) #

print(d3, type(d3)) # [(1, "A"), (3, "B"), (2, "C")]

print(d4, type(d4)) # [(2, "C"), (3, "B"), (1, "A")]

[(1, ‘A"), (3, ‘B"), (2, ‘C")]

[(2, ‘C"), (3, ‘B"), (1, ‘A")]

sorted排序list

①按一种规则排序list

from operator import itemgetter

data = [("c", 3, "Apple"), ("d", 1, "Cat"), ("a", 2, "Banana")]

# 根据字母升序

print(sorted(data, key=lambda x: x[0], reverse=False)) #

# 根据数字升序

print(sorted(data, key=lambda x: x[1], reverse=False)) #

# 根据单词升序

print(sorted(data, key=lambda x: x[2], reverse=False)) #

[("a", 2, "Banana"), ("c", 3, "Apple"), ("d", 1, "Cat")]

[("d", 1, "Cat"), ("a", 2, "Banana"), ("c", 3, "Apple")]

[("c", 3, "Apple"), ("a", 2, "Banana"), ("d", 1, "Cat")]

②按多种规则排序list

# 先按照成绩降序排序，相同成绩的按照名字升序排序：

d1 = [{"name":"alice", "score":38}, {"name":"bob", "score":18}, {"name":"darl", "score":28}, {"name":"christ", "score":28}]

l = sorted(d1, key=lambda x:(-x["score"], x["name"]))

print(l)

[{"name": "alice", "score": 38}, {"name": "christ", "score": 28}, {"name": "darl", "score": 28}, {"name": "bob", "score": 18}]

sorted排序list和dict的混合

先看看我们排序的有哪些类型的数据结构

#### 二维list排序

l1 = [["Bob", 95.00, "A"], ["Alan", 86.0, "C"], ["Mandy", 82.5, "A"], ["Rob", 86, "E"]]

#### list中混合字典

l2 = [{"name":"alice", "score":38}, {"name":"bob", "score":18}, {"name":"darl", "score":28}, {"name":"christ", "score":28}]

#### 字典中混合list

d1 = {"Li": ["M", 7], "Zhang": ["E", 2], "Wang": ["P", 3], "Du": ["C", 2], "Ma": ["C", 9], "Zhe": ["H", 7]}

#### 对字典中的多维list进行排序

d2 = {

"Apple": [["44", 88], ["11", 33], ["22", 88]],

"Banana": [["55", 43], ["11", 68], ["44", 22]],

"Orange":[["22", 22], ["55", 41], ["44", 42], ["33", 22]]

}

二维list排序

from operator import itemgetter

l1 = [["Bob", 95.00, "A"], ["Alan", 86.0, "C"], ["Mandy", 82.5, "A"], ["Rob", 86, "E"]]

# 按先按成绩号升序，再按成绩数值升序

print(sorted(l1, key=itemgetter(2, 1), reverse=False))

# 按先按成绩号升序，再按成绩数值降序序

print(sorted(l1, key=lambda x:(x[2], -x[1]), reverse=False))

[[‘Mandy", 82.5, ‘A"], [‘Bob", 95.0, ‘A"], [‘Alan", 86.0, ‘C"], [‘Rob", 86, ‘E"]]

[[‘Bob", 95.0, ‘A"], [‘Mandy", 82.5, ‘A"], [‘Alan", 86.0, ‘C"], [‘Rob", 86, ‘E"]]

2. list中混合字典

from operator import itemgetter

# 先按照成绩降序排序，相同成绩的按照名字升序排序：

l2 = [{"name":"alice", "score":38}, {"name":"bob", "score":18}, {"name":"darl", "score":28}, {"name":"christ", "score":28}]

print(sorted(l2, key=lambda x:(-x["score"], x["name"])))

print(sorted(l2, key=itemgetter("score", "name")))

[{‘name": ‘alice", ‘score": 38}, {‘name": ‘christ", ‘score": 28}, {‘name": ‘darl", ‘score": 28}, {‘name": ‘bob", ‘score": 18}]

[{‘name": ‘bob", ‘score": 18}, {‘name": ‘christ", ‘score": 28}, {‘name": ‘darl", ‘score": 28}, {‘name": ‘alice", ‘score": 38}]

3. 字典中混合list

d1 = {"Li": ["M", 7], "Zhang": ["E", 2], "Wang": ["P", 3], "Du": ["C", 2], "Ma": ["C", 9], "Zhe": ["H", 7]}

# sort返回的是list，如果需要转为dict，再sorted前面套一个dict()就可以了

print(sorted(d1.items(), key=lambda x:(x[1][1], -ord(x[1][0]) ))) # 对字符比较需要ord。如果是"123"字符串数字可以使用int。

# print(sorted(d1.items(), key=lambda x:(x[1][1], -ord(x[1][0]) )))

[(‘Zhang", [‘E", 2]), (‘Du", [‘C", 2]), (‘Wang", [‘P", 3]), (‘Li", [‘M", 7]), (‘Zhe", [‘H", 7]), (‘Ma", [‘C", 9])]

4. 对字典中的多维list进行排序

d2 = {

"Apple": [["44", 88], ["11", 33], ["22", 88]],

"Banana": [["55", 43], ["11", 68], ["44", 22]],

"Orange":[["22", 22], ["55", 41], ["44", 42], ["33", 22]]

}

for key, value in d2.items():

d2[key] = sorted(value, key=lambda x:(x[1], -int(x[0]))) # 按list第二列升序，相同则按第一列降序，参考二维list排序

print(d2)

{‘Apple": [[‘11", 33], [‘44", 88], [‘22", 88]], ‘Banana": [[‘44", 22], [‘55", 43], [‘11", 68]], ‘Orange": [[‘33", 22], [‘22", 22], [‘52", 41], [‘44", 42]]}

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原文链接：https://blog.csdn.net/Spade_/article/details/106601727