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对给出的列表进行词频统计,将单词与单词出现次数对应起来,以字典的形式输出
列表如下
l1=['a','a','b','b','b','c','c','c','c','d','d','d','d']
- l1=['a','a','b','b','b','c','c','c','c','d','d','d','d']
- print(l1)
- b=dict.fromkeys(l1,0)
- print(b)
- for x in l1:
- b[x]+=1
- print(b)
'运行
输出结果:
- ['a', 'a', 'b', 'b', 'b', 'c', 'c', 'c', 'c', 'd', 'd', 'd', 'd']
- {'a': 0, 'b': 0, 'c': 0, 'd': 0}
- {'a': 2, 'b': 3, 'c': 4, 'd': 4}
'运行
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