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- import math
-
- def calculate_min_transport_rounds_optimized(vehicles, capacities, distances, total_stones, strategy='max_capacity'):
- n = len(vehicles)
- if strategy == 'max_capacity':
- # 按承载能力降序排序
- vehicles_capacities = sorted(zip(vehicles, capacities), key=lambda x: x[1], reverse=True)
- elif strategy == 'longest_distance':
- # 按距离降序排序
- vehicles_distances = sorted(zip(vehicles, distances), key=lambda x: x[1], reverse=True)
-
- min_rounds = 0
- stones_left = total_stones
-
- while stones_left > 0:
- min_rounds += 1
- if strategy == 'max_capacity':
- # 每次尽可能多地运输石头
- capacity_used = 0
- for vehicle, capacity in vehicles_capacities:
- if stones_left <= 0:
- break
- if capacity >= stones_left:
- capacity_used = stones_left
- stones_left = 0
- else:
- capacity_used += capacity
- stones_left -= capacity
- elif strategy == 'longest_distance':
- # 优先运输距离较长的石头
- for vehicle, distance in vehicles_distances:
- if stones_left <= 0:
- break
- capacity = capacities[vehicles.index(vehicle)]
- if capacity >= stones_left:
- stones_left = 0
- else:
- stones_left -= capacity
-
- return min_rounds
-
- # 示例数据
- vehicles = ["船", "马车", "外星飞船"]
- capacities = [1000, 500, 2000] # 对应每辆车的承载能力
- distances = [50, 20, 80] # 对应每块石头到达施工现场的距离
- total_stones = 10000 # 假设需要运输的石头总数
-
- # 计算最小运输次数(按每次尽可能多地运输石头策略)
- min_rounds_max_capacity = calculate_min_transport_rounds_optimized(vehicles, capacities, distances, total_stones, strategy='max_capacity')
- print(f"按每次尽可能多地运输石头策略,完成运输任务所需的最小运输次数为: {min_rounds_max_capacity}")
-
- # 计算最小运输次数(按优先运输距离较长的石头策略)
- min_rounds_longest_distance = calculate_min_transport_rounds_optimized(vehicles, capacities, distances, total_stones, strategy='longest_distance')
- print(f"按优先运输距离较长的石头策略,完成运输任务所需的最小运输次数为: {min_rounds_longest_distance}")
问题1:建立数学模型,收集相关数据,以最大的赫夫金字塔为例 ,计算在给定的运输车辆数量和载重量下,完成石料运输任务所需的最小运输次数。
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