Python从入门到实践第九章习题9-15_python编程从入门到实践9-15

9-15彩票分析是python第二版新加的题目，对于小白来说极为不友好。找了半天也没有找到这道题的答案，记录一下这次完成的答案。

from random import choice
def get_winning_ticket(possibilities):
    """摇出中奖组合。"""
    winning_ticket = []
    # 中奖组合中不能包含重复的数字或字母，因此使用了 while 循环。
    while len(winning_ticket) < 4:
        pulled_item = choice(possibilities)
 # 仅当摇出的数字或字母不在组合中时，才将其添加到组合中。
        if pulled_item not in winning_ticket:
            pulled_item = choice(possibilities)
            # 仅当摇出的数字或字母不在组合中时，才将其添加到组合中。
        if pulled_item not in winning_ticket:
            winning_ticket.append(pulled_item)
    return winning_ticket
def check_ticket(played_ticket, winning_ticket):
 # 检查彩票的每个数字或字母，只要有一个不在中奖组合中，就返回 False。
    for element in played_ticket:
        if element not in winning_ticket:
            return False
    # 如果代码执行到这里，就说明中奖了!
    return True
def make_random_ticket(possibilities):
    """随机地生成彩票。"""
    ticket = []
    # 彩票不能包含重复的数字或字母，因此使用了 while 循环。
    while len(ticket) < 4:
        pulled_item = choice(possibilities)

 # 仅当随机生成的数字或字母不在彩票中时，才将其添加到彩票中。
        if pulled_item not in ticket:
            ticket.append(pulled_item)

    return ticket
possibilities = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 'a', 'b', 'c', 'd', 'e']
winning_ticket = get_winning_ticket(possibilities)

plays = 0
won = False
# 为避免程序执行时间太长，设置最多随机生成多少张彩票。
max_tries = 1_000_000
while not won:
    new_ticket = make_random_ticket(possibilities)
    won = check_ticket(new_ticket, winning_ticket)
    plays += 1
    if plays >= max_tries:
        break
if won:
 print("We have a winning ticket!")
 print(f"Your ticket: {new_ticket}")
 print(f"Winning ticket: {winning_ticket}")
 print(f"It only took {plays} tries to win!")
else:
 print(f"Tried {plays} times, without pulling a winner. :(")
 print(f"Your ticket: {new_ticket}")
 print(f"Winning ticket: {winning_ticket}")
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