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Future value with different compounding frequencies. Initial investment $ 100 100 100 at an 8 % 8\% 8% rate grows.
Compounding Frequency | Number of times per year | Future value in one year |
---|---|---|
Annual | 1 | 108 = 100 × ( 1 + 8 % ) 108=100\times(1+8\%) 108=100×(1+8%) |
Semi-annual | 2 | 108.16 = 100 × ( 1 + 8 % 2 ) 2 108.16=100\times(1+\frac{8\%}{2})^2 108.16=100×(1+28%)2 |
Quarterly | 4 | 108.24 = 100 × ( 1 + 8 % 4 ) 4 108.24=100\times(1+\frac{8\%}{4})^4 108.24=100×(1+48%)4 |
Monthly | 12 | 108.30 = 100 × ( 1 + 8 % 12 ) 12 108.30=100\times(1+\frac{8\%}{12})^{12} 108.30=100×(1+128%)12 |
Weekly | 52 | 108.32 = 100 × ( 1 + 8 % 52 ) 52 108.32=100\times(1+\frac{8\%}{52})^{52} 108.32=100×(1+528%)52 |
Daily | 365 | 108.33 = 100 × ( 1 + 8 % 365 ) 365 108.33=100\times(1+\frac{8\%}{365})^{365} 108.33=100×(1+3658%)365 |
Present value with different compounding frequencies $ 100 100 100 received in five years when the interest rate is 8 % 8\% 8%.
Compounding Frequency | Number of times per year | Present value in five year |
---|---|---|
Annual | 1 | 68.06 = 100 × ( 1 + 8 % ) − 5 68.06=100\times(1+8\%)^{-5} 68.06=100×(1+8%)−5 |
Semi-annual | 2 | 67.56 = 100 × ( 1 + 8 % 2 ) − 5 × 2 67.56=100\times(1+\frac{8\%}{2})^{-5\times2} 67.56=100×(1+28%)−5×2 |
Quarterly | 4 | 67.30 = 100 × ( 1 + 8 % 4 ) − 5 × 4 67.30=100\times(1+\frac{8\%}{4})^{-5\times4} 67.30=100×(1+48%)−5×4 |
Monthly | 12 | 67.12 = 100 × ( 1 + 8 % 12 ) − 5 × 12 67.12=100\times(1+\frac{8\%}{12})^{-5\times12} 67.12=100×(1+128%)−5×12 |
Weekly | 52 | 67.05 = 100 × ( 1 + 8 % 52 ) − 5 × 52 67.05=100\times(1+\frac{8\%}{52})^{-5\times52} 67.05=100×(1+528%)−5×52 |
Daily | 365 | 67.03 = 100 × ( 1 + 8 % 365 ) − 5 × 365 67.03=100\times(1+\frac{8\%}{365})^{-5\times365} 67.03=100×(1+3658%)−5×365 |
In the limit of the compounding frequency, we obtain continuous compounding.
Future value: If an interest rate R R R is continuously compounded, it can be shown that an amount A A A grows to A e R T Ae^{RT} AeRT by time T T T.
Present value: The present value of an amount A A A received at time T T T is A e − R T Ae^{-RT} Ae−RT.
Convert
R
1
R_1
R1 (compounded
m
1
m_1
m1 times per annum) to the equivalent rate
R
2
R_2
R2(compounded
m
2
m_2
m2 times per annum):
(
1
+
R
1
m
1
)
m
1
=
(
1
+
R
2
m
2
)
m
2
(1+\frac{R_1}{m_1})^{m_1}=(1+\frac{R_2}{m_2})^{m_2}
(1+m1R1)m1=(1+m2R2)m2
Convert R m R_m Rm (compounded m m m times per annum) to the equivalent rate R c R_c Rc (continuously compounded rate).
e R c = ( 1 + R m m ) m e^{R_c}=(1+\frac{R_m}{m})^{m} eRc=(1+mRm)m
In the United States and some other countries, bonds which last longer than one year from date of issue normally pay interest every six months. The yield provided by a bond is therefore normally expressed with semi-annual compounding.
Discount Factor is the present value of one unit of currency to be received at the end of that term. The discount factor is a declining function of maturity due to the time-value of money phenomenon)
d ( 1.5 ) = 0.9825 d(1.5)=0.9825 d(1.5)=0.9825, means that the present value of $1 to be received in 18 months is $0.9825 today.
Discount factor from T-bills(零息债券)
A Treasury bill maturing in 6 months is worth USD 995 , 912.50 995,912.50 995,912.50 now, and its par value is USD 1 million.What is the six-month discount factor?
d ( 0.5 ) = 995 , 912.50 1 , 000 , 000 = 0.9959125 d(0.5)=\frac{995,912.50}{1,000,000}=0.9959125 d(0.5)=1,000,000995,912.50=0.9959125
Discount factor from coupon-bearing bonds(付息债券)
A six-month bond that pays coupons at the rate of 5 % 5\% 5% per year is currently worth 100.5 100.5 100.5. What is the six-month discount factor?
d ( 0.5 ) = 100.5 100 + 2.5 = 0.980488 d(0.5)=\frac{100.5}{100+2.5}=0.980488 d(0.5)=100+2.5100.5=0.980488
In addition to the bond in the example above, a one-year bond that pays coupons every six months at the rate of 3 % 3\% 3% per year is currently worth 98.5 98.5 98.5. What is the one-year discount factor?
1.5 ∗ d ( 0.5 ) + 101.5 ∗ d ( 1 ) = 98.5 → d ( 1 ) = 0.955953 1.5*d(0.5)+101.5*d(1)=98.5\to d(1)=0.955953 1.5∗d(0.5)+101.5∗d(1)=98.5→d(1)=0.955953
Annuity is a finite set of level sequential cash flows.
An investor deposits $ 2000 2000 2000 at the beginning of the following four years into an account that pays nominal annual interest of 6 % 6\% 6% (compounding monthly). The value of the account at the end of four years is closest to:
The equivalent annual rate = ( 1 + 6 % / 12 ) 12 − 1 = 6.1678 % (1+6\%/12)^{12}-1=6.1678\% (1+6%/12)12−1=6.1678%
Calculator: [2nd][PMT], [2nd][ENTER] → \to → BGN mode
N = 4 N=4 N=4, 1 / Y = 6.1678 1/Y=6.1678 1/Y=6.1678, P V = 0 PV=0 PV=0, P M T = 2000 PMT=2000 PMT=2000 → \to → C P T F V = 9312 CPT \;FV=9312 CPTFV=9312
Annuity Factor: The sum of the discount factors, assume semi-annual basis
A
T
=
∑
t
=
1
2
n
d
(
t
2
)
AT= \sum^{2n}_{t=1}d(\frac{t}{2})
AT=t=1∑2nd(2t)
Perpetuity is a security that pays coupons forever. The price of a perpetuity is simply the coupon divided by the yield.
Perpetuity = C y \text{Perpetuity}=\frac{C}{y} Perpetuity=yC
The spot rate is the interest rate earned when cash is received at just one future time. It is also referred to as the zero-coupon interest rate, or just the “zero”.
Direct way: derive spot rates from money market instruments lasting less than one year.
Bootstrap: instruments lasting longer than one year usually make regular payments prior to maturity.
One way of calculating the zero-coupon rates implied by these instruments is by working forward and fitting the zero-coupon rates to progressively longer maturity instruments.
Calculate the zero rates for 6 months, one year, 18 months and two years using bootstrapping.
Time to Maturity | Bond Par Value($) | Coupon Rate (semi-annual) | Bond Price($) |
---|---|---|---|
0.5 0.5 0.5 | 100 100 100 | 0 % 0\% 0% | 98.5 98.5 98.5 |
1 1 1 | 100 100 100 | 0 % 0\% 0% | 95.9 95.9 95.9 |
1.5 1.5 1.5 | 100 100 100 | 4 % 4\% 4% | 98 98 98 |
2 2 2 | 100 100 100 | 6 % 6\% 6% | 100.6 100.6 100.6 |
100 1 + z 0.5 / 2 = 98.5 → z 0.5 = 3.05 % \frac{100}{1+z_{0.5}/2}=98.5\to z_{0.5}=3.05\% 1+z0.5/2100=98.5→z0.5=3.05%
100 ( 1 + z 1 / 2 ) 2 = 95.9 → z 1 = 4.23 % \frac{100}{(1+z_{1}/2)^2}=95.9\to z_{1}=4.23\% (1+z1/2)2100=95.9→z1=4.23%
2 1 + z 0.5 / 2 + 2 ( 1 + z 1 / 2 ) 2 + 102 ( 1 + z 1.5 / 2 ) 3 = 98 → z 1.5 = 5.44 % \frac{2}{1+z_{0.5}/2}+\frac{2}{(1+z_{1}/2)^2}+\frac{102}{(1+z_{1.5}/2)^3}=98\to z_{1.5}=5.44\% 1+z0.5/22+(1+z1/2)22+(1+z1.5/2)3102=98→z1.5=5.44%
3 1 + z 0.5 / 2 + 3 ( 1 + z 1 / 2 ) 2 + 3 ( 1 + z 1.5 / 2 ) 3 + 103 ( 1 + z 1.5 / 2 ) 3 = 100.6 → z 2 = 5.73 % \frac{3}{1+z_{0.5}/2}+\frac{3}{(1+z_{1}/2)^2}+\frac{3}{(1+z_{1.5}/2)^3}+\frac{103}{(1+z_{1.5}/2)^3}=100.6\to z_{2}=5.73\% 1+z0.5/23+(1+z1/2)23+(1+z1.5/2)33+(1+z1.5/2)3103=100.6→z2=5.73%
Spot rate give the same information as discount factors.
Suppose the discount factor for
t
t
t years is
d
(
t
)
d(t)
d(t) and that the
t
t
t-year spot rate is
z
(
t
)
z(t)
z(t) with semi-annual compound
d
(
t
)
=
1
(
1
+
z
(
t
)
2
)
2
t
→
z
(
t
)
=
2
[
(
1
d
(
t
)
)
1
2
t
−
1
]
d(t)=\frac{1}{(1+\frac{z(t)}{2})^{2t}}\to z(t)=2[(\frac{1}{d(t)})^{\frac{1}{2t}}-1]
d(t)=(1+2z(t))2t1→z(t)=2[(d(t)1)2t1−1]
Computing spot rates from STRIPS prices or discount factors for semi-annual compounding.
Terms in years | 0.5 | 1 | 1.5 | 2 | 2.5 | 3 |
---|---|---|---|---|---|---|
STRIP Price | 99.206349 99.206349 99.206349 | 97.932618 97.932618 97.932618 | 96.413232 96.413232 96.413232 | 94.683986 94.683986 94.683986 | 92.826033 92.826033 92.826033 | 90.915462 90.915462 90.915462 |
Discount Factor | 0.992063 0.992063 0.992063 | 0.979326 0.979326 0.979326 | 0.964132 0.964132 0.964132 | 0.946840 0.946840 0.946840 | 0.928260 0.928260 0.928260 | 0.909155 0.909155 0.909155 |
d ( 0.5 ) = 1 ( 1 + Z 0.5 2 ) = 0.992063 → Z 0.5 = 1.6 % d(0.5)=\frac{1}{(1+\frac{Z_{0.5}}{2})}=0.992063 \to Z_{0.5}=1.6\% d(0.5)=(1+2Z0.5)1=0.992063→Z0.5=1.6%
d ( 1 ) = 1 ( 1 + Z 1 2 ) 2 = 0.979326 → Z 1 = 2.1 % d(1)=\frac{1}{(1+\frac{Z_1}{2})^2}=0.979326 \to Z_1=2.1\% d(1)=(1+2Z1)21=0.979326→Z1=2.1%
d ( 1.5 ) = 1 ( 1 + Z 1.5 2 ) 3 = 0.964132 → Z 1 = 2.45 % d(1.5)=\frac{1}{(1+\frac{Z_{1.5}}{2})^3}=0.964132 \to Z_1=2.45\% d(1.5)=(1+2Z1.5)31=0.964132→Z1=2.45%
Law of one price assets that produce identical future cash flows regardless of future events should have the same price.
The valuation of bond involves identifying its cash flows and discounting them at the interest rates corresponding to their maturities.
Use a sequence of spot rates that correspond to the cash flow dates to calculate the bond price.
P
=
∑
t
=
1
n
C
(
1
+
Z
t
)
t
+
F
V
(
1
+
Z
n
)
n
P=\sum^n_{t=1}\frac{C}{(1+Z_t)^t}+\frac{FV}{(1+Z_n)^n}
P=t=1∑n(1+Zt)tC+(1+Zn)nFV
Assume a 1.5-year bond with a face value of $ 100 100 100 pays a 3.5 % 3.5\% 3.5% coupon on a semiannual basis. What is the price of the bond according to the following spot rates?
Maturity(years) | 0.5 0.5 0.5 | 1 1 1 | 1.5 1.5 1.5 | 2 2 2 |
---|---|---|---|---|
Spot rate | 2.2 % 2.2\% 2.2% | 2.25 % 2.25\% 2.25% | 2.30 % 2.30\% 2.30% | 2.35 % 2.35\% 2.35% |
Price = 1.75 ( 1 + 2.2 % / 2 ) + 1.75 ( 1 + 2.25 % / 2 ) 2 + 101.75 ( 1 + 2.3 % / 2 ) 3 = 101.7611 \text{Price}=\frac{1.75}{(1+2.2\%/2)}+\frac{1.75}{(1+2.25\%/2)^2}+\frac{101.75}{(1+2.3\%/2)^3}=101.7611 Price=(1+2.2%/2)1.75+(1+2.25%/2)21.75+(1+2.3%/2)3101.75=101.7611
Forward rates are interest rates corresponding to a future period implied by the spot curve.
All forward rates are computed using spot rates.
Annual compounding z 1 z_1 z1 is 3%, z 2 z_2 z2 is 4%. The implied forward rate from the end of year one to the end of year two is:
( 1 + 3 % ) ( 1 + F ) = ( 1 + 4 % ) 2 → F = 5.01 % (1+3\%)(1+F)=(1+4\%)^2 \to F=5.01\% (1+3%)(1+F)=(1+4%)2→F=5.01%
Semi-annual compounding z 0.5 z_{0.5} z0.5 is 1.6%, z 1 z_1 z1 is 2.1%. The implied forward rate from the end of half-year to the end of year one is:
( 1 + 1.6 % 2 ) ( 1 + F 2 ) = ( 1 + 2.1 % 2 ) 2 → F = 2.6 % (1+\frac{1.6\%}{2})(1+\frac{F}{2})=(1+\frac{2.1\%}{2})^2 \to F=2.6\% (1+21.6%)(1+2F)=(1+22.1%)2→F=2.6%
Continuous compounding z 3 z_3 z3 is 4.5%, z 4 z_4 z4 is 5%. The implied forward rate from the end of year three to year four is:
e 0.045 × 3 × e F × 1 = e 0.05 × 4 → F = 6.5 % e^{0.045\times 3}\times e^{F\times 1}=e^{0.05\times 4} \to F=6.5\% e0.045×3×eF×1=e0.05×4→F=6.5%
When rates are expressed with ordinary compounding, the forward rate for the period between time T 1 T_1 T1 and T 2 T_2 T2 is
( 1 + R 1 ) T 1 ( 1 + F 1 , 2 ) T 2 − T 1 = ( 1 + R 2 ) T 2 (1+R_1)^{T_1}(1+F_{1,2})^{T_2-T_1}=(1+R_2)^{T_2} (1+R1)T1(1+F1,2)T2−T1=(1+R2)T2
When rates are expressed with continuous compounding, the forward rate for the period between time
T
1
T_1
T1 and
T
2
T_2
T2 is
F
=
R
2
T
2
−
R
1
T
1
T
2
−
T
1
F=\frac{R_2T_2-R_1T_1}{T_2-T_1}
F=T2−T1R2T2−R1T1
An investor can borrow funds for time T 1 T_1 T1 and invest for T 2 T_2 T2. If the rates for the period between T 1 T_1 T1 and T 2 T_2 T2 are less than the forward rate, the investor’s total financing cost will be less than the investor’s return, producing a profit.
Suppose the two-year rate is 4 % 4\% 4% and the three-year rate is 5 % 5\% 5%, with both rates continuously compounded. So the forward rate for the third year is 7 % 7\% 7%.
Forward rates can be used to value a bond in the same manner as spot rates because they are interconnected.
Discount bond cash flows one period by one period with forward rates.
Example: suppose an analyst needs to value a 1.5 year, 3% semi-annual coupon payment bond.What is the price of the bond according to the following forward rates?
Term in Years | 0-0.5 | 0.5-1 | 1-1.5 |
---|---|---|---|
6-month Forward Rates | 2.5% | 3.5% | 3.78% |
1.5 1 + 2.5 % 2 + 1.5 ( 1 + 2.5 % 2 ) ( 1 + 3.5 % 2 ) + 101.5 ( 1 + 2.5 % 2 ) ( 1 + 3.5 % 2 ) ( 1 + 3.78 % 2 ) = 99.6327 \frac{1.5}{1+\frac{2.5\%}{2}}+\frac{1.5}{(1+\frac{2.5\%}{2})(1+\frac{3.5\%}{2})}+\frac{101.5}{(1+\frac{2.5\%}{2})(1+\frac{3.5\%}{2})(1+\frac{3.78\%}{2})}=99.6327 1+22.5%1.5+(1+22.5%)(1+23.5%)1.5+(1+22.5%)(1+23.5%)(1+23.78%)101.5=99.6327
Par rate is the coupon rate which bond is priced at par value.
For an asset with a par amount of one unit that makes semiannual payments and matures in T T T years
p 2 ∑ t = 1 2 t d ( t 2 ) + d ( T ) = 1 → A ( T ) = ∑ t = 1 2 t d ( t 2 ) \frac{p}{2}\sum^{2t}_{t=1}d(\frac{t}{2})+d(T)=1 \to A(T)=\sum^{2t}_{t=1}d(\frac{t}{2}) 2pt=1∑2td(2t)+d(T)=1→A(T)=t=1∑2td(2t)
Assume a 1.5-year bond pays semiannual coupons and has a par value of $ 100 100 100, please compute the 1.5-year par rate.
Maturity | 0.5 | 1 | 1.5 |
---|---|---|---|
Discount factor | 0.992063 0.992063 0.992063 | 0.979326 0.979326 0.979326 | 0.964132 0.964132 0.964132 |
p × 100 2 [ d ( 0.5 ) + d ( 1 ) + d ( 1.5 ) ] + d ( 1.5 ) × 100 = 100 → p = 2.44 % \frac{p\times 100}{2}[d(0.5)+d(1)+d(1.5)]+d(1.5) \times 100=100 \to p=2.44\% 2p×100[d(0.5)+d(1)+d(1.5)]+d(1.5)×100=100→p=2.44%
Based on the assumption of semi-annual compounding, calculate the spot rate in 1.5 years
Term in Years | Discount Factor | Spot Rate | Forward Rate | Par Rate |
---|---|---|---|---|
0.5 | 0.992063 0.992063 0.992063 | 1.60 % 1.60\% 1.60% | 1.6000 % 1.6000\% 1.6000% | 1.60 % 1.60\% 1.60% |
1 | 0.979326 0.979326 0.979326 | 2.10 % 2.10\% 2.10% | 2.6012 % 2.6012\% 2.6012% | 2.10 % 2.10\% 2.10% |
1.5 | 0.964132 0.964132 0.964132 | 2.45 % 2.45\% 2.45% | 3.1518 % 3.1518\% 3.1518% | 2.44 % 2.44\% 2.44% |
2 | 0.946840 0.946840 0.946840 | 2.75 % 2.75\% 2.75% | 3.6537 % 3.6537\% 3.6537% | 2.74 % 2.74\% 2.74% |
2.5 | 0.928260 0.928260 0.928260 | 3.00 % 3.00\% 3.00% | 4.0031 % 4.0031\% 4.0031% | 2.98 % 2.98\% 2.98% |
3 | 0.909155 0.909155 0.909155 | 3.20 % 3.20\% 3.20% | 4.2030 % 4.2030\% 4.2030% | 3.18 % 3.18\% 3.18% |
3.5 | 0.888696 0.888696 0.888696 | 3.40 % 3.40\% 3.40% | 4.6041 % 4.6041\% 4.6041% | 3.37 % 3.37\% 3.37% |
4 | 0.863598 0.863598 0.863598 | 3.70 % 3.70\% 3.70% | 5.8124 % 5.8124\% 5.8124% | 3.65 % 3.65\% 3.65% |
From discount factor
d ( 1.5 ) = 1 ( 1 + Z 1.5 2 ) 3 → Z 1.5 = 2.45 % d(1.5)=\frac{1}{(1+\frac{Z_{1.5}}{2})^3} \to Z_{1.5}=2.45\% d(1.5)=(1+2Z1.5)31→Z1.5=2.45%
From forward rate
(
1
+
Z
1.5
2
)
3
=
(
1
+
f
0
−
0.5
2
)
(
1
+
f
0.5
−
1
2
)
(
1
+
f
1
−
1.5
2
)
(1+\frac{Z_{1.5}}{2})^3=(1+\frac{f_{0-0.5}}{2})(1+\frac{f_{0.5-1}}{2})(1+\frac{f_{1-1.5}}{2})
(1+2Z1.5)3=(1+2f0−0.5)(1+2f0.5−1)(1+2f1−1.5)
From par rate
100
=
2.44
/
2
(
1
+
1.6
%
2
)
+
2.44
/
2
(
1
+
2.1
%
2
)
2
+
100
+
2.44
/
2
(
1
+
Z
1.5
%
2
)
3
100=\frac{2.44/2}{(1+\frac{1.6\%}{2})}+\frac{2.44/2}{(1+\frac{2.1\%}{2})^2}+\frac{100+2.44/2}{(1+\frac{Z_{1.5}\%}{2})^3}
100=(1+21.6%)2.44/2+(1+22.1%)22.44/2+(1+2Z1.5%)3100+2.44/2
Term structure
If spot curve is upward-slopping
If spot curve is downward-slopping
If the term structure is flat(with all the spot rates the same), all par rates and all forward rates equal to the spot rate.
Government borrowing rates is interest rate paid by a government on its borrowings in its own currency. In the U.S., this is referred to as the Treasury Rate.
Government debt from developed countries is considered to be risk-free and the interest rates on these borrowings are generally below those on other borrowings in the same currency.
In a repo agreement, securities are sold by Party A and Party B for a certain price with the intention of being repurchased at a later time at higher price.
If Party A fails to repurchase the securities as agreed, Party B can simply keep the securities. This means that Party B takes very little risk, provided that:
Libor (London Interbank Offered Rate): an unsecured borrowing rate between banks. Libor rates are quoted for several different currencies and for borrowing periods ranging one day to one year.
Libor is a less than ideal benchmark because it is based on estimates that can be manipulated.
Two replacement benchmark rate:
The repo overnight rate: The United States has proposed the use of the repo-based Secured Overnight Financing Rate (SOFR).
Overnight interbank borrowing rate: arises from unsecured borrowing and lending between banks at the end of each day to keep cash in reserve with central bank.
Swap rate is the fixed portion of a swap as determined by its particular market and the parties involved.
Floating rates are based on some short-term reference interest rate, such as three-month or six-month dollar Libor(London Interbank Offered Rate).
The swap market therefore defines par rates. For example, the five-year swap rate defines a five-year bond selling for par. The par rates can be used to determine discount factors and therefore spot rates.
Overnight index swap(OIS): the geometric average of overnight rates is exchanged for a fixed rate every three months for five years.
OIS rates are the fixed rates in overnight indexed swaps.
The floating rate per three-months is
(
1
+
r
1
d
1
)
(
1
+
r
2
d
2
)
…
(
1
+
r
n
d
n
)
−
1
(1+r_1d_1)(1+r_2d_2) \ldots (1+r_nd_n)-1
(1+r1d1)(1+r2d2)…(1+rndn)−1
The risk-free rates used to value derivatives are determined from overnight interbank rates using overnight indexed swaps. Treasury rates are not used because they are considered to be artificially low.
Parallel shift: The yields on all maturities increase or decrease by the same number of basis points maintaining its prior slope and shape.
Non-Parallel Shift: The yields on all maturities increase or decrease by different number of basis points and non-parallel shift changes the slope of the yield curve
A flattening term structure occurs
A steepening term structure occurs
The market segmentation theory: argues that short-, medium-, and long-maturity instruments attract different types of traders.
The expectations theory: argues that the interest rate term structure reflects where the market is expecting interest rates to be in the future.
The liquidity preference theory: if the interest rate term structure reflects what the market expects interest rates to be in the future, most investors will choose a short-term investment over a long-term investment. This is because of liquidity consideration. Liquidity considerations therefore lead to lenders wanting to lend for short periods of time and borrowers wanting to borrow for long periods of time.
In order to match borrowers and lenders, financial intermediaries must increase long-term rates relative to the market’s expectations about future short-term rates.
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