Golang | Leetcode Golang题解之第234题回文链表

题目：

题解：

func reverseList(head *ListNode) *ListNode {
    var prev, cur *ListNode = nil, head
    for cur != nil {
        nextTmp := cur.Next
        cur.Next = prev
        prev = cur
        cur = nextTmp
    }
    return prev
}
 
func endOfFirstHalf(head *ListNode) *ListNode {
    fast := head
    slow := head
    for fast.Next != nil && fast.Next.Next != nil {
        fast = fast.Next.Next
        slow = slow.Next
    }
    return slow
}
 
func isPalindrome(head *ListNode) bool {
    if head == nil {
        return true
    }
 
    // 找到前半部分链表的尾节点并反转后半部分链表
    firstHalfEnd := endOfFirstHalf(head)
    secondHalfStart := reverseList(firstHalfEnd.Next)
 
    // 判断是否回文
    p1 := head
    p2 := secondHalfStart
    result := true
    for result && p2 != nil {
        if p1.Val != p2.Val {
            result = false
        }
        p1 = p1.Next
        p2 = p2.Next
    }
 
    // 还原链表并返回结果
    firstHalfEnd.Next = reverseList(secondHalfStart)
    return result
}