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- #include <iostream>
- #include <stack>
- #include <string>
- #include <regex>
- using namespace std;
-
- bool priority(char top, char b){
- if(top == '('){//为左括号
- return false;
- }
- if(top == '-' || top == '+' && b == '*'){
- return false;//高则压栈
- }
- if((top == '+' || top == '-') && (b == '+' || b == '-')){
- return false;
- }
- else{
- return true;//计算
- }
- }
-
- void compute(stack<int>& s1, stack<char>& s2){
- int b = s1.top();
- s1.pop();
- int a = s1.top();
- s1.pop();
- char ch = s2.top();
- s2.pop();
- int sum = 0;
- if(ch == '+'){
- sum = a + b;
- }
- else if(ch == '-'){
- sum = a - b;
- }
- else{
- sum = a*b;
- }
- s1.push(sum);
- }
-
- int main() {
- //先找到最长的数学表达式子
- string s;
- getline(cin, s);
- //查找最长合法数学表达式
- regex math("(-?\\d+)([\\*+-]\\d+)*"); // 定义正则表达式,匹配数字和操作符序列
- sregex_iterator it(s.begin(), s.end(), math);//允许遍历一个字符串中所有符合正则表达式的子串
- sregex_iterator end;
- string longstr = "";
- while(it != end){
- if(it->str().size() > longstr.size()){
- longstr = it->str();
- }
- it++;
- }
- longstr = longstr + ')';//加上右括号
- stack<int> arr;
- stack<char> symbol;
- string temp = "";
- symbol.push('(');//先压入左括号
- bool flag = false;//标记是负号还是减号
- for(int i = 0; i < longstr.size(); i++){
- if(longstr[i] >= '0' && longstr[i <='9']){
- temp += longstr[i];
- }
- else if(longstr[i] == ')'){//如果是右括号
- flag = false;//后续的第一个-为负号
- arr.push(stoi(temp));
- temp = "";
- while(symbol.top()!='('){
- compute(arr, symbol);
- }
- symbol.pop();
- }
- else if(longstr[i] == '-'){
- if(!flag){//第一次出现-
- temp += '-';
- flag = true;
- }
- else{//是符号
- arr.push(stoi(temp));
- temp = "";
- while(priority(symbol.top(), longstr[i])){
- compute(arr, symbol);
- }
- symbol.push(longstr[i]);//不计算,压栈
- }
- }
- else{//是其他符号
- flag = true;//下次遇到的-为符号
- arr.push(stoi(temp));
- temp = "";
- while(priority(symbol.top(), longstr[i])){
- compute(arr, symbol);
- }
- symbol.push(longstr[i]);
- }
- }
- cout << arr.top() << endl;
- }
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