python interpolate 4d_python脚本纠错：interpolate.interp2d的正确用法

说明：

所以在插值前，加两句把输入参数变成一维数组

XX = np.arange(0, 16, 1)

YY= np.arange(0, 12, 1)

代码：

from matplotlib import pyplot as plt

import numpy as np

from mpl_toolkits.mplot3d import Axes3D

from scipy import interpolate

import matplotlib as mpl

import matplotlib.cm as cm

fig = plt.figure()

Z=np.empty([12,16])

#ax = Axes3D(fig)

ax = fig.add_subplot(121, projection='3d')

bx = fig.add_subplot(122, projection='3d')

adc=[

29.38, 29.28, 29.23, 29.35, 29.53, 29.49, 29.41, 29.34, 29.42, 29.46, 29.58, 29.55, 29.49, 29.35, 29.46, 30.07,

29.43, 29.36, 29.39, 29.34, 29.55, 29.54, 29.44, 2