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1 | 2 | 3 | 4 | 5 | |||||
哪天返回 | 猴子分香蕉 | 字母阵列 | 第几个幸运数 | 书号验证 | |||||
6 | 7 | 8 | 9 | 10 | |||||
打印大X | 缩位求和 | 等腰三角形 | 小朋友崇拜圈 | 耐摔指数 |
11
- package 哪天返回;
-
- public class Main {
- public static void main(String[] args) {
- int money = 1;
- int sum = 0;
- for (int i = 1; ; i++,money+=2) {
- sum+=money;
- System.err.println("第"+i+"天 :"+sum);
- if (sum >= 108) {
- break;
- }
- }
- }
- }
- package 猴子分香蕉;
- public class Main {
- public static void main(String[] args) {
- for (int i = 17; i < 1000000; i++) {
- int num = i;
- if (num % 5 == 1) {
- num=num-1;
- num -= (num/5);
- if (num%5==2) {
- num -= 2;
- num -= (num/5);
- if (num%5==3) {
- num-=3;
- num -=(num/5);
- if (num%5==4) {
- num-=4;
- num-=(num/5);
- if (num%5==0) {
- System.out.println(i);
- return;
- }
- }
- }
- }
- }
- }
- }
- }
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41
- package 字母阵列;
-
- import java.util.Scanner;
-
- public class Main {
- static int count = 0;
- public static void main(String[] args) {
- Scanner sr = new Scanner(System.in);
- //创建地图
- char[][] map = new char[100][100];
- for (int i = 0; i < map.length; i++) {
- String s = sr.next();
- map[i] = s.toCharArray();
- }
- //寻找L起点
- for (int i = 0; i < map.length; i++) {
- for (int j = 0; j < map[0].length; j++) {
- dfs(i, j, map);//以此位置为起点
- }
- }
- System.out.println(count);
- }
-
- private static void dfs(int i, int j, char[][] map) {
- //LANQIAO
- String Model = "LANQIAO";
- //方向移动数组
- int[] dx = {1,-1,0,0,-1,-1,1,1};
- int[] dy = {0,0,-1,1,-1,1,-1,1};
- for (int k = 0; k < 8; k++) {
- int nx = i;//起点位置
- int ny = j;
- int step = 0;//字符匹配计数器
- //按此方向循环蓝桥长度
- for (int p = 0; p < Model.length(); p++) {
- nx += dx[k];
- ny += dy[k];
- if (nx >= 0 && ny >= 0 && nx < map.length && ny < map[0].length && map[nx][ny] == Model.charAt(p)) {
- step++;
- continue;
- }else {
- break;
- }
- }//此方向完美匹配长度,count++;
- if (step == Model.length()) count++;
- }
-
- return;
- }
- }
1905
- package 第几个幸运数;
-
- public class Main {
- public static void main(String[] args) {
- // 统计最后的幸运数
- int count = 0;
- // 数字太大所以用Long型,数字最后+L表示形式!!因为JAVA默认int类型~
- Long num = 59084709587505L;
- for (int i = 0; Math.pow(3, i) < num; i++) { // 3的i次方<num
- for (int j = 0; Math.pow(5, j) < num; j++) { // 5的j次方<num
- for (int k = 0; Math.pow(7, k) < num; k++) { // 7的k次方<num
- if (Math.pow(3, i) * Math.pow(5, j) * Math.pow(7, k) <= num) { // 如果三个次方同时相乘<num,继续循环!!
- count++; // 求得幸运数结果
- }
- }
- }
- }
- // 千万注意,因为i,j,k的for初始值为0,0没有意义,所以在原结果-1,求得答案1905!!
- System.out.println(count - 1);
- }
- }
- package 书号验证;
-
- public class Main
- {
- static boolean f(String s){
- int k=1;
- int sum = 0;
- for(int i=0; i<s.length(); i++){
- char c = s.charAt(i);
- if(c=='-' || c==' ') continue;
- sum += (c-'0')*(k%2==0?3:1); //填空
- k++;
- if(k>12) break;
- }
-
- return s.charAt(s.length()-1)-'0' == (10-sum % 10)%10;
- }
-
- public static void main(String[] args){
- System.out.println(f("978-7-301-04815-3"));
- System.out.println(f("978-7-115-38821-6"));
- }
- }
- package 打印大X;
-
-
- public class Main
- {
- static void f(int h, int w){
- System.out.println(String.format("高度=%d, 笔宽=%d",h,w));
- int a1 = 0;
- int a2 = h - 1;
-
- for(int k=0; k<h; k++){
- int p = Math.min(a1,a2);
- int q = Math.max(a1+w,a2+w);
-
- for(int i=0; i<p; i++) System.out.print(" ");
-
- if(q-p<w*2){
- for(int i = p ; i < q ;i++)System.out.print("*"); ; //填空
- }
- else{
- for(int i=0; i<w; i++) System.out.print("*");
- for(int i=0; i<q-p-w*2; i++) System.out.print(" ");
- for(int i=0; i<w; i++) System.out.print("*");
- }
- System.out.println();
- a1++;
- a2--;
- }
- }
-
- public static void main(String[] args){
- f(15,3);
- f(8,5);
- }
- }
- package 缩位求和;
-
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- Scanner sr = new Scanner(System.in);
- String s = sr.next();
-
- while (s.length() > 1) {
- int num = 0;
- for (int i = 0; i < s.length(); i++) {
- num += s.charAt(i)-'0';
- }
- s = num+"";
- }
- System.out.println(s);
- }
- }
- 例如:
- 输入:
- 5
-
- 程序应该输出:
- ....1
- ...2.1
- ..3...2
- .4.....1
- 567891011
-
- 再例如:
- 输入:
- 10
-
- 程序应该输出:
- .........1
- ........2.2
- .......3...2
- ......4.....2
- .....5.......1
- ....6.........2
- ...7...........0
- ..8.............2
- .9...............9
- 1011121314151617181
-
- 再例如:
- 输入:
- 15
-
- 程序应该输出:
-
- ..............1
- .............2.3
- ............3...2
- ...........4.....3
- ..........5.......1
- .........6.........3
- ........7...........0
- .......8.............3
- ......9...............9
- .....1.................2
- ....0...................8
- ...1.....................2
- ..1.......................7
- .1.........................2
- 21314151617181920212223242526
-
-
- 资源约定:
- 峰值内存消耗(含虚拟机) < 256M
- CPU消耗 < 1000ms
- package 数字三角形;
-
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- Scanner sr = new Scanner(System.in);
- int n =sr.nextInt();
- String str = "";
- for (int i = 1; i <= n*2+3; i++) {
- str += i;
- }
- //计算整个字串长度
- int len = ( n-1 ) + ( n*2-1 ) + ( n-2 );
- str = str.substring(0,len);
- String left = str.substring(0,(n-1));
- String down = str.substring((n-1) ,(n-1) + (n*2-1));
- String right = str.substring((n-1) + (n*2-1) , len);
- right = new StringBuilder(right).reverse().toString();
- // System.out.println(left);
- // System.out.println(down);
- // System.out.println(right);
- //行
- for (int j = n-1; j >= 1; j--)
- System.out.print(".");
- System.out.println(left.charAt(0));
-
- for (int i = 2; i < n; i++) {
- //输出前置*
- for (int j = n-i; j >= 1; j--)
- System.out.print(".");
- //左
- System.out.print(left.charAt(i-1));
- //输出中间*
- for (int j = 1; j <= i-2; j++)
- System.out.print("..");
- System.out.print(".");
- //右
- System.out.println(right.charAt(i-2));
- }
- System.out.println(down);
- }
- }
- package 小朋友崇拜圈;
-
- import java.util.ArrayList;
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- Scanner sr = new Scanner(System.in);
- int n = sr.nextInt();
- int max = 0;//最大值圈
- int[] child = new int[n+1];//存储小朋友崇拜的人,序号1开始,所以+1
- for (int i = 1; i < child.length; i++) {
- child[i] = sr.nextInt();
- }
- //遍历起点
- for (int i = 1; i < child.length; i++) {
- //从这个起点开始寻找崇拜圈
- ArrayList<Integer> list = new ArrayList<Integer>();
- list.add(i);
- while (!list.isEmpty()) {
- //看看刚加进来的小朋友崇拜谁
- int id = child[list.get(list.size()-1)];
- //这个人之前被崇拜你的人崇拜过,形成圈
- if (list.contains(id)) {
- System.out.print(list+" ");
- System.out.println(list.size() - list.indexOf(id));
- max = Math.max(max, list.size() - list.indexOf(id));
- break;
- }//寻找新加进来的整个人崇拜的人
- list.add(id);
- }
- }
- System.out.println(max );
- }
- }
- package 耐摔次数;
-
- public class Main {
-
- public static void main(String[] args) {
-
- int[][] dp = new int[1000+1][3+1];
- //手机数量为1时的测试次数了
- for (int i = 1; i < dp.length; i++) {
- dp[i][1] = i;
- }
- for (int i = 1; i < dp.length; i++) {
- //由于上面已经设置了手机数量为1时的测试次数了
- //所以只需从手机数量为2开始进行遍历即可
- for (int j = 2; j < dp[0].length; j++) {
- //取一个不影响结果的数
- int min = Integer.MAX_VALUE;
- //从第1层到第 i 层,逐一尝试所有决策,取最优的
- //每一层最坏情况下(max 测试次数最多)的最好结果(min)
- for (int k = 1; k <= i; k++) {
- min = Math.min(min,
- Math.max(dp[k-1][j-1], dp[i-k][j]));
- }
- //需要加上本次测试的次数,因此需要+1
- dp[i][j]=min+1;
- }
- }
- System.out.println(dp[1000][3]);
- }
- }
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