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了解kafka分区重平衡的概念,了解分区重新分配的三种策略。
- <dependency>
- <groupId>org.apache.kafka</groupId>
- <artifactId>kafka-clients</artifactId>
- <version>3.2.0</version>
- </dependency>
本文相关概念参考了kafka官网以及官网推荐的书籍Kafka The Defi nitive Guide(kafka定义指南)。
所有权
消费者和分区之间的映射通常称为消费者对分区的所有权。
分区重平衡
将分区所有权从一个消费者移动到另一个消费者被称为重新平衡。
group coordinator
每个消费者组都有一个组协调员(group coordinator)。
group leader
第一个加入消费者组的消费者成为这个消费者组的组长(group leader)
group leader从group coordinator获取组内消费者列表信息,并负责为每个消费者分配分区子集。它使用PartitionAssignor的实现来决定哪些分区应由哪个消费者处理。
重新平衡很重要,因为它们为消费者组提供了高可用性和可扩展性(允许我们轻松安全地添加和删除消费者),但在正常情况下,它们是相当不受欢迎的。在重新平衡期间,消费者不能使用消息,这使消费者组处于一个不可用的短期状态。此外,当分区从一个消费者移动到另一个消费者时,消费者将丢失其当前状态;如果它正在缓存任何数据,则需要刷新其缓存,这会减慢应用程序的速度,直到消费者再次设置其状态。
官网文档
A list of class names or class types, ordered by preference, of supported partition assignment strategies that the client will use to distribute partition ownership amongst consumer instances when group management is used. Available options are:
org.apache.kafka.clients.consumer.RangeAssignor
: Assigns partitions on a per-topic basis.org.apache.kafka.clients.consumer.RoundRobinAssignor
: Assigns partitions to consumers in a round-robin fashion.org.apache.kafka.clients.consumer.StickyAssignor
: Guarantees an assignment that is maximally balanced while preserving as many existing partition assignments as possible.org.apache.kafka.clients.consumer.CooperativeStickyAssignor
: Follows the same StickyAssignor logic, but allows for cooperative rebalancing.The default assignor is [RangeAssignor, CooperativeStickyAssignor], which will use the RangeAssignor by default, but allows upgrading to the CooperativeStickyAssignor with just a single rolling bounce that removes the RangeAssignor from the list.
Implementing the
org.apache.kafka.clients.consumer.ConsumerPartitionAssignor
interface allows you to plug in a custom assignment strategy.
Type: list Default: class org.apache.kafka.clients.consumer.RangeAssignor,class org.apache.kafka.clients.consumer.CooperativeStickyAssignor Valid Values: non-null string Importance: medium
根据官网描述,分区重平衡共有三种策略,分别是:
官方文档对该策略的定义
截取部分描述
The range assignor works on a per-topic basis. For each topic, we lay out the available partitions in numeric order and the consumers in lexicographic order. We then divide the number of partitions by the total number of consumers to determine the number of partitions to assign to each consumer. If it does not evenly divide, then the first few consumers will have one extra partition.
翻译过来的意思
该策略按照顺序分配分区给消费者,具体的做法是:分区数量➗消费者总数=每个消费者分配的分区数量,如果分配不均衡,则优先给前面的消费者多分配一个分区。概念图如下:
官方文档对该策略的定义
截取部分描述
The round robin assignor lays out all the available partitions and all the available consumers. It then proceeds to do a round robin assignment from partition to consumer. If the subscriptions of all consumer instances are identical, then the partitions will be uniformly distributed. (i.e., the partition ownership counts will be within a delta of exactly one across all consumers.)
For example, suppose there are two consumers
C0
andC1
, two topicst0
andt1
, and each topic has 3 partitions, resulting in partitionst0p0
,t0p1
,t0p2
,t1p0
,t1p1
, andt1p2
.The assignment will be:
C0: [t0p0, t0p2, t1p1]
C1: [t0p1, t1p0, t1p2]
When subscriptions differ across consumer instances, the assignment process still considers each consumer instance in round robin fashion but skips over an instance if it is not subscribed to the topic. Unlike the case when subscriptions are identical, this can result in imbalanced assignments. For example, we have three consumers
C0
,C1
,C2
, and three topicst0
,t1
,t2
, with 1, 2, and 3 partitions, respectively. Therefore, the partitions aret0p0
,t1p0
,t1p1
,t2p0
,t2p1
,t2p2
.C0
is subscribed tot0
;C1
is subscribed tot0
,t1
; andC2
is subscribed tot0
,t1
,t2
.That assignment will be:
Since the introduction of static membership, we could leverage
C0: [t0p0]
C1: [t1p0]
C2: [t1p1, t2p0, t2p1, t2p2]
group.instance.id
to make the assignment behavior more sticky. For example, we have three consumers with assignedmember.id
C0
,C1
,C2
, two topicst0
andt1
, and each topic has 3 partitions, resulting in partitionst0p0
,t0p1
,t0p2
,t1p0
,t1p1
, andt1p2
. We choose to honor the sorted order based on ephemeralmember.id
.The assignment will be:
After one rolling bounce, group coordinator will attempt to assign new
C0: [t0p0, t1p0]
C1: [t0p1, t1p1]
C2: [t0p2, t1p2]
member.id
towards consumers, for exampleC0
->C5
C1
->C3
,C2
->C4
.The assignment could be completely shuffled to:
This issue could be mitigated by the introduction of static membership. Consumers will have individual instance ids
C3 (was C1): [t0p0, t1p0] (before was [t0p1, t1p1])
C4 (was C2): [t0p1, t1p1] (before was [t0p2, t1p2])
C5 (was C0): [t0p2, t1p2] (before was [t0p0, t1p0])
I1
,I2
,I3
. As long as 1. Number of members remain the same across generation 2. Static members' identities persist across generation 3. Subscription pattern doesn't change for any memberThe assignment will always be:
I0: [t0p0, t1p0]
I1: [t0p1, t1p1]
I2: [t0p2, t1p2]
翻译过来的意思
分区按照循环的方式分配给消费者,如果所有消费者订阅的主题相同,则分区将均匀分布。概念图如下:
如果消费者订阅的主题不同则可能导致分配不平衡。假如:
每个消费者则分区分配如下:
官网文档对该策略的定义
该策略初始分配分区给消费者和round-robin相似,但是一旦重平衡,则round-robin策略会重新初始化分配,而sticky则根据两项原则分配,原则一优于原则二:
从原则二来看,这或许就是该策略命名为sticky(粘性的)的原因。
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