2.5D瓦块地图坐标转换_unity 2.5d 坐标转换

很多瓦块地形都是2.5D的视角呈现世界，在网上查了一些资料，发现从直角坐标变换到2.5D的坐标需做两步：一、旋转45度，二、再把瓦块地图的高压缩一半。

 于是乎，第一步旋转后的坐标，比如那个黑色的点的坐标，可以通过计算公式得到：

 然后用C#程序来实现是这个样子：

 C#程序实现如下：

using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
 
namespace _25Dpoint
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }
 
        private void Form1_Paint(object sender, PaintEventArgs e)
        {            
            Graphics g = this.CreateGraphics(); 
            SolidBrush brushBlack = new SolidBrush(Color.Black);
 
            g.DrawLine(Pens.Black, 200, 0, 200, 400); //画出直角坐标系的x,y轴
            g.DrawLine(Pens.Black, 0, 200, 400, 200);
 
            float x1 = 20, y1 = 180;   //假设黑点的坐标为20，180 （这个坐标数字是WIN屏幕的坐标，从直角坐标系到WIN屏幕坐标系是不同的，需要转换一下）
 
            Point winpoint1 = screen_point(x1, y1); //直角坐标系到WIN屏幕坐标系
            g.DrawString(winpoint1.X.ToString() + "," + winpoint1.Y.ToString(), Font, brushBlack, winpoint1.X, winpoint1.Y); //显示字符串
            g.FillEllipse(brushBlack, winpoint1.X, winpoint1.Y, 5, 5);        //显示点
 
            float x2 = (float) (x1 * Math.Cos(-45) - y1 * Math.Sin(-45)); //坐标转轴公式 顺时针转45度
            float y2 = (float) (x1 * Math.Sin(-45) + y1 * Math.Cos(-45)); 
 
            Point winpoint2 = screen_point(x2, y2);
            g.FillEllipse(brushBlack, winpoint2.X, winpoint2.Y, 5, 5); //显示字符串
            g.DrawString(winpoint2.X.ToString() + "," + winpoint2.Y.ToString(), Font, brushBlack, winpoint2.X, winpoint2.Y); //显示转换后的点
 
 
        }
 
        public Point screen_point(float cartX, float cartY)
        {
            Point screenpoint =  new Point();
            screenpoint.X = (int) cartX + ( 400/2  );
            screenpoint.Y = (400/2) - (int)cartY;
 
            return screenpoint;
        }
    }
}