java从异常里获取入参信息_java – 使用Spring AOP处理异常时获取传递给方法的参数的值...

在我的方面类的方法中,我想获取参数的值和参数的名称.

如果我没有得到名称仍然可以,但我需要获取传递的参数的值是否可能？

(ptCut表达式没有问题,该方法被调用我用sysouts检查)

我的Aspect方法是这样的：

public void excpetionHappened(Exception e) {

// Log the exception

// log the name of the method name/signature which caused the exception

// log the value of the input parameters to the method

// wrap and throw new exctn

}

提前致谢.

解决方法:

你可以使用周围的建议.

这使得在处理异常时可以访问参数.

public aspect ExceptionReporterAspect {

/** The name of the used logger. */

public final static String LOGGER_NAME = "AspectJExceptionLogger";

/** Logger used to log messages. */

private static final Log LOGGER = LogFactory.getLog(LOGGER_NAME);

pointcut stringRequestHandler() :

execution (@RequestMapping Object the.package..*(..));

Object around(): objectRequestHandler(){

try {

return proceed();

} catch (Exception ex){

Signature sig = thisJoinPointStaticPart.getSignature();

Object[] args = thisJoinPoint.getArgs();

String location = sig.getDeclaringTypeName() + '.' + sig.getName() + ", args=" + Arrays.toString(args);

LOGGER.warn("(AOP detected) exception within " + location, ex);

throw(ex)

}

}

}

标签：java,exception-handling,spring,spring-aop

来源： https://codeday.me/bug/20190630/1334574.html