最长公共子序列算法思想的应用_算法中最长公共子序列的应用

最长公共子序列解答：

public class Test1 {
 
    public static void main(String[] args) {
        char[] chars1 = "ABCBDAB".toCharArray();
        char[] chars2 = "BDCABA".toCharArray();
        LCS(chars1, chars2);
    }
 
    public static void LCS(char[] chars1, char[] chars2) {  // 最长公共子序列
        int len1 = chars1.length;
        int len2 = chars2.length;
        int[][] dp = new int[len1+1][len2+1];
        dp[0][0] = 0;
        for(int i = 1; i <= len1; i++) {
            for(int j = 1; j <= len2; j++) {
                if(chars1[i-1] == chars2[j-1]) {
                    dp[i][j] = dp[i-1][j-1] + 1;
                }
                else {
                    dp[i][j] = Math.max(dp[i-1][j], dp[i][j-1]);
                }
            }
        }
//        System.out.println(dp[len1][len2]);   // 最长公共子序列长度
        getres(dp, len1, len2, chars1);
    }
 
    public static void getres(int[][] dp, int i, int j, char[] chars) {
        StringBuilder sb = new StringBuilder();
        while(i != 0 && j != 0) {
            if(dp[i][j] == dp[i-1][j]) i--;
            else if(dp[i][j] == dp[i][j-1]) j