python 获取函数的参数名字

def df(a, b,c):
    return a,b,c
    
def get_func_args(func, stripself=False):
    import inspect
    from functools import partial, wraps
    """Return the argument name list of a callable object"""
    if not callable(func):
        raise TypeError(f"func must be callable, got '{type(func).__name__}'")

    args = []
    try:
        sig = inspect.signature(func)
    except ValueError:
        return args

    if isinstance(func, partial):
        partial_args = func.args
        partial_kw = func.keywords

        for name, param in sig.parameters.items():
            if param.name in partial_args:
                continue
            if partial_kw and param.name in partial_kw:
                continue
            args.append(name)
    else:
        for name in sig.parameters.keys():
            args.append(name)

    if stripself and args and args[0] == "self":
        args = args[1:]
    return args
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返回结果：
[‘a’, ‘b’, ‘c’]