python头歌-python第六章作业_列表的属性与方法头歌平台第六章答案

第1关 列表的属性与方法

def main(n):
    ls = []
    for i in range(n):
        lsinput = input().split()
        operate = lsinput[0]
        if operate == 'insert':
            ls.insert(int(lsinput[1]),int(lsinput[2]))
        elif operate == 'remove':
            ls.remove(int(lsinput[1]))
        elif operate == 'append':
            ls.append(int(lsinput[1]))
        elif operate == 'sort':
            ls.sort()
        elif operate == 'pop':
            ls.pop()    
        elif operate == 'reverse':
            ls.reverse()
        elif operate == 'print':
            print(ls)
if __name__ == '__main__':
    N = int(input())
    main(N)

第2关 推导式与生成器

ls = ['the lord of the rings','anaconda','legally blonde','gone with the wind']
s = input()        # 输入一个字符
# 当输入为"1"时，输出元素为0-9的3次方的列表 [0, 1, 8, 27, 64, 125, 216, 343, 512, 729]
if s == '1':
    print([x ** 3 for x in range(10)])
# 当输入为"2"时，输出元素为0-9中偶数的3次方的列表 [0, 8, 64, 216, 512]
elif s == '2':
    print([x ** 3 for x in range(10) if x % 2 == 0])
 # 当输入为"3"时，输出元素为元组的列表，元组中元素依次是0-9中的奇数和该数的3次方[(1, 1), (3, 27), (5, 125), (7, 343), (9, 729)]
elif s == '3':
     print([(x,x ** 3) for x in range(10) if x % 2 == 1])
# 当输入为"4"时，将ls中每个元素单词首字母大写输出['The lord of the rings', 'Anaconda', 'Legally blonde', 'Gone with the wind']
elif s == '4':
    print([s.capitalize() for s in ls])
# 当输入为其他字符时，执行以下语句
else:
    print("结束程序")

第3关 列表的合并与排序

lst_a = list(map(int,input().split()))
lst_b = list(map(int,input().split()))
lst_ab = lst_a + lst_b
lst_ab.sort(reverse=True)
print(lst_ab)

第4关 二维列表排序

m = int(input())
n = int(input())
myList = [('dungeon',7),('winterfell',4),('bran',9),('meelo',6)]
if m > len(myList):
    m = len(myList)
print(sorted(myList,key=lambda x:x[1])[:m])
score = [[ 'Angle', '0121701100106',99],[ 'Jack', '0121701100107',86],[ 'Tom',   '0121701100109',65],[ 'Smith', '0121701100111',100],['Bob','0121701100115',77],['Lily','0121701100117',59]]
if n > len(score):
    n = len(score)
print(sorted(score,key=lambda x:x[0])[:n])
print(sorted(score,key=lambda x:x[2])[:n])

第5关 动物重量排序

ls = []
while True:
    temp = input()
    if temp == '':
        break
    ls.append(temp.split())
print(sorted(ls,key=lambda x:float(x[1][:-1])*1000 if x[1][-1] == 't' else float(x[1][:-2])))

第6关 身份证号升位

n = input()
list1 = list(n)
Wi=[7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2]
if int(list1[6])+int(list1[7]) >= 5:
    list1.insert(6,9)
    list1.insert(6,1)
else:
    list1.insert(6,0)
    list1.insert(6,2)
s = 0
for i in range(17):
    s +=  int(list1[i]) * int(Wi[i])
m = s % 11
list2 = [1,0,'X',9,8,7,6,5,4,3,2]
list1.append(list2[m])
for x in list1:
    print(*str(x),end = '')

第7关 完美立方数

N = int(input())
for a in range(2,N+1):
    for b in range(2,a):
        for c in range(b,a):
            for d in range(c,a):
                if a**3 == b**3+c**3+d**3:
                    print(f'Cube = {a},Triple = ({b},{c},{d})')

第8关 约瑟夫环问题

def Josephus(n,k):
    ls_n=list(range(1,n+1))
    while len(ls_n)>k-1:
        ls_n=ls_n[k:]+ls_n[:k-1]
    return ls_n
n,k=map(int,input().split())
if k>=2 and n>=k:
    print(Josephus(n,k))
else:
    print('Data Error!')

第9关 统计英文文件中的单词数

def read_file(file):
    """接收文件名为参数，读取文件中的数据到字符串中，返回这个字符串"""
    with open(file, 'r', encoding='utf-8') as text:  # 创建文件对象
        txt =text.read()      # 读文件为字符串
    return txt     # 返回字符串
 
 
def word_list(txt):
    """接收字符串为参数，用空格替换字符串中所有标点符号，根据空格将字符串切分为列表
    返回值为元素为单词的列表"""
    for i in ",.!\'":
        txt = txt.replace(i, ' ')
    return txt.split()
 
 
def number_of_words(ls):
    """接收一个以单词为元素的列表为参数，返回列表中单词数量，返回值为整型"""
    return len(ls)
 
 
if __name__ == '__main__':
    filename = input()                          # 读入文件名
    text = read_file('step10/'+filename)        # 读取'step10/'文件夹中用户输入的文件名得到文件内容，存入text
    words_list = word_list(text)                # 处理text,得到单词的列表
    words_counts = number_of_words(words_list)  #统计单词列表word_list里的单词数
    print(f'共有{words_counts}个单词')