37种传感器-树莓派开发-7-震动开关_python如何触发手机振动

C语言编程

本次的震动开关还是一样的原理，但是代码有了不小改动。这个震动开关在震动时产生的高频信号是瞬间的，所以在接收了一次高频信号后切换一次，有点类似轻触开关的延迟。

#include <wiringPi.h>
#include <stdio.h>

#define VibratePin	0
#define Gpin		1
#define Rpin		2

int tmp = 0;

void LED(int color)
{
	pinMode(Gpin, OUTPUT);
	pinMode(Rpin, OUTPUT);
	if (color == 0)
	{
		digitalWrite(Rpin, HIGH);
		digitalWrite(Gpin, LOW);
	}
	else if (color == 1)
	{
		digitalWrite(Rpin, LOW);
		digitalWrite(Gpin, HIGH);
	}
	else
		printf("LED Error");
}

void Print(int x){
	if (x != tmp){
		if (x == 0)
			printf("...ON\n");
		if (x == 1)
			printf("OFF..\n");
		tmp = x;
	}
}

int main(void)
{
	int status = 0;
	int tmp = 0;
	int value = 1;
	if(wiringPiSetup() == -1){ //when initialize wiring failed,print messageto screen
		printf("setup wiringPi failed !");
		return 1; 
	}

	pinMode(VibratePin, INPUT);
	
	while(1){
		value = digitalRead(VibratePin);
		if (tmp != value){
			status ++;
			if (status > 1){
				status = 0;
			}
			LED(status);	
			Print(status);
			delay(1000);
		}
	}
	return 0;
}
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PS：status只是用来交替颜色使用，并没有计数。接收一次高频信号后，status得到1，再接收一次信号后status变成2后又归零，导致status只有0和1两个值。

Python

#!/usr/bin/env python
import RPi.GPIO as GPIO
import time

VibratePin = 11
Gpin   = 12
Rpin   = 13

tmp = 0

def setup():
	GPIO.setmode(GPIO.BOARD)       # Numbers GPIOs by physical location
	GPIO.setup(Gpin, GPIO.OUT)     # Set Green Led Pin mode to output
	GPIO.setup(Rpin, GPIO.OUT)     # Set Red Led Pin mode to output
	GPIO.setup(VibratePin, GPIO.IN, pull_up_down=GPIO.PUD_UP)    # Set BtnPin's mode is input, and pull up to high level(3.3V)

def Led(x):
	if x == 0:
		GPIO.output(Rpin, 1)
		GPIO.output(Gpin, 0)
	if x == 1:
		GPIO.output(Rpin, 0)
		GPIO.output(Gpin, 1)
	

def Print(x):
	global tmp
	if x != tmp:
		if x == 0:
			print '    **********'
			print '    *     ON *'
			print '    **********'
	
		if x == 1:
			print '    **********'
			print '    * OFF    *'
			print '    **********'
		tmp = x

def loop():
	state = 0
	while True:
		if GPIO.input(VibratePin):
			state = state + 1
			if state > 1:
				state = 0
			Led(state)
			Print(state)
			time.sleep(1)

def destroy():
	GPIO.output(Gpin, GPIO.HIGH)       # Green led off
	GPIO.output(Rpin, GPIO.HIGH)       # Red led off
	GPIO.cleanup()                     # Release resource

if __name__ == '__main__':     # Program start from here
	setup()
	try:
		loop()
	except KeyboardInterrupt:  # When 'Ctrl+C' is pressed, the child program destroy() will be  executed.
		destroy()
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python编程也是如此，利用同样的逻辑，不过利用input引脚是否接收到信号，以接收到为准，改变status。