赞
踩
进阶:你能尝试使用一趟扫描实现吗?
示例 1:
输入:head = [1,2,3,4,5], n = 2
输出:[1,2,3,5]
示例 2:
输入:head = [1], n = 1
输出:[]
示例 3:
输入:head = [1,2], n = 1
输出:[1]
class Solution {
public:
int getLength(ListNode* head){
int length = 0;
while(head){
++length;
head = head->next;
}
return length;
}
ListNode* removeNthFromEnd(ListNode* head, int n) {
ListNode* dummy = new ListNode(0,head);
int length = getLength(head);
ListNode* cur = dummy;
for(int i = 1;i<length - n+1;++i){
cur = cur->next;
}
cur->next = cur->next->next;
ListNode* ans = dummy->next;
delete dummy;
return ans;
}
};
ListNode dummy = new ListNode(0,head);:创建哑节点。
Copyright © 2003-2013 www.wpsshop.cn 版权所有,并保留所有权利。