乐鑫提前批编程题 7.6_鑫池刘鑫池 yiew navigate code relactor rn tools vcs win

第一题，一个老头分财产，老大拿最大的，老二拿第二大。接下来总财产小的拿，如果一样就老大拿，判断最后多的比少的多拿多少？

双指针

#include<iostream>
#include<vector>
#include<algorithm>
 
using namespace std;
int main()
{
 
	int n;
	cin >> n;
	vector<int>vec(2*n);
	for (int k = 0; k < 2 * n; k++)
	{
		
		cin>>vec[k];
	}
 
 	sort(vec.begin(), vec.end());
	//双指针
	int i = vec.size() - 1, j = vec.size() - 2;
	int son1 = vec[i], son2 =vec[j];
	while (i > 0 && j > 0)
	{
		if (son1 > son2)
		{
			j--;
			i -= 3;
			son1 = son1 + vec[i];
			son2 = son2 + vec[j];
			
		}
		else
		{
			i--;
			j -= 3;
			son1 = son1 + vec[i];
			son2 = son2 + vec[j];
			
		}
 
	}
	cout << son1 - son2;
 
}