IP报文分片抓包简析_ip报文抓包分析

IP报文分片

发送1472

• ICMP报文长度8+IP头部20+数据1472=1500（最大MTU），故而不会进行IP报文拆包

# 发送ping
[root@localhost ~]# ping -c 10 -s 1472 192.168.0.10
PING 192.168.0.10 (192.168.0.10) 1472(1500) bytes of data.
1480 bytes from 192.168.0.10: icmp_seq=1 ttl=64 time=0.133 ms
1480 bytes from 192.168.0.10: icmp_seq=2 ttl=64 time=0.060 ms
1480 bytes from 192.168.0.10: icmp_seq=3 ttl=64 time=0.074 ms
1480 bytes from 192.168.0.10: icmp_seq=4 ttl=64 time=0.045 ms
1480 bytes from 192.168.0.10: icmp_seq=5 ttl=64 time=0.056 ms
1480 bytes from 192.168.0.10: icmp_seq=6 ttl=64 time=0.069 ms
1480 bytes from 192.168.0.10: icmp_seq=7 ttl=64 time=0.068 ms
1480 bytes from 192.168.0.10: icmp_seq=8 ttl=64 time=0.160 ms
1480 bytes from 192.168.0.10: icmp_seq=9 ttl=64 time=0.064 ms
1480 bytes from 192.168.0.10: icmp_seq=10 ttl=64 time=0.064 ms
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可见此时没有分片

发送5000

# 发送ping包
[root@localhost ~]# ping -c 5 -s 5000 10.70.2.1
PING 10.70.2.1 (10.70.2.1) 5000(5028) bytes of data.
5008 bytes from 10.70.2.1: icmp_seq=1 ttl=128 time=6.47 ms
5008 bytes from 10.70.2.1: icmp_seq=2 ttl=128 time=2.14 ms
5008 bytes from 10.70.2.1: icmp_seq=3 ttl=128 time=2.35 ms
5008 bytes from 10.70.2.1: icmp_seq=4 ttl=128 time=9.83 ms
5008 bytes from 10.70.2.1: icmp_seq=5 ttl=128 time=2.97 ms

--- 10.70.2.1 ping statistics ---
5 packets transmitted, 5 received, 0% packet loss, time 4007ms
rtt min/avg/max/mdev = 2.142/4.757/9.837/2.985 ms
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注：

1. Identification(10037)一样的表示属于同一个IP报文的
2. offset=0的表示为第一个分片，最后一个offset=（1480纯数据）+（1480纯数据）+（1480纯数据）=4440（该值表示之前已经发送了3*1480字节的数据，后续要需要发送560字节数据，然后再构建最后一个数据包时560+8（icmp）+20（IP头部）+ 16（MAC层）=604总包大小）