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1.现将数字n对10取余
2.再将数字n对10取整
3.循环第一,二步即可
#include <iostream> using namespace std; int main(void) { int n,right_digit; cout<<"Enter the number:"; cin>>n; cout<<"The number in reverse order is "; do { right_digit = n%10; cout <<right_digit; n/=10; } while(n!=0); cout<<endl; }
调试结果:
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