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机器学习 - 梯度下降在多参数线性回归模型的应用以及解析

机器学习 - 梯度下降在多参数线性回归模型的应用以及解析

我们通过一个具体的例子来演示多变量线性回归中的梯度下降算法

示例数据集

假设我们有一个简单的数据集,包含两个特征和一个目标值:

(x_1)(x_2)(y)
125
238
3411
4514

我们要训练一个线性回归模型,模型的形式为:
f w , b ( x ) = w 1 ⋅ x 1 + w 2 ⋅ x 2 + b f_{w,b}(x) = w_1 \cdot x_1 + w_2 \cdot x_2 + b fw,b(x)=w1x1+w2x2+b

梯度下降步骤

我们从随机初始化的参数 w 1 w_1 w1 w 2 w_2 w2 b b b 开始,然后通过梯度下降算法迭代地更新这些参数。

初始化

假设:

  • 初始权重 w 1 = 0 w_1 = 0 w1=0 w 2 = 0 w_2 = 0 w2=0
  • 初始偏置 b = 0 b = 0 b=0
  • 学习率 α = 0.01 \alpha = 0.01 α=0.01
  • 迭代次数为 2 次(为了简洁)

计算梯度

我们需要计算每个参数的偏导数,并用这些偏导数来更新参数。

第一次迭代

计算偏导数
  1. 计算预测值和误差:
    预测值 f w , b ( x ( i ) ) = w 1 ⋅ x 1 ( i ) + w 2 ⋅ x 2 ( i ) + b \text{预测值} \quad f_{w,b}(x^{(i)}) = w_1 \cdot x_1^{(i)} + w_2 \cdot x_2^{(i)} + b 预测值fw,b(x(i))=w1x1(i)+w2x2(i)+b
    对于每个样本,我们计算预测值和误差:

    • 对于第一个样本 (1, 2, 5):
      f w , b ( x ( 1 ) ) = 0 ⋅ 1 + 0 ⋅ 2 + 0 = 0 误差 = 0 − 5 = − 5 f_{w,b}(x^{(1)}) = 0 \cdot 1 + 0 \cdot 2 + 0 = 0 \\ \text{误差} \quad = 0 - 5 = -5 fw,b(x(1))=01+02+0=0误差=05=5
    • 对于第二个样本 (2, 3, 8):
      f w , b ( x ( 2 ) ) = 0 ⋅ 2 + 0 ⋅ 3 + 0 = 0 误差 = 0 − 8 = − 8 f_{w,b}(x^{(2)}) = 0 \cdot 2 + 0 \cdot 3 + 0 = 0 \\ \text{误差} \quad = 0 - 8 = -8 fw,b(x(2))=02+03+0=0误差=08=8
    • 对于第三个样本 (3, 4, 11):
      f w , b ( x ( 3 ) ) = 0 ⋅ 3 + 0 ⋅ 4 + 0 = 0 误差 = 0 − 11 = − 11 f_{w,b}(x^{(3)}) = 0 \cdot 3 + 0 \cdot 4 + 0 = 0 \\ \text{误差} \quad = 0 - 11 = -11 fw,b(x(3))=03+04+0=0误差=011=11
    • 对于第四个样本 (4, 5, 14):
      f w , b ( x ( 4 ) ) = 0 ⋅ 4 + 0 ⋅ 5 + 0 = 0 误差 = 0 − 14 = − 14 f_{w,b}(x^{(4)}) = 0 \cdot 4 + 0 \cdot 5 + 0 = 0 \\ \text{误差} \quad = 0 - 14 = -14 fw,b(x(4))=04+05+0=0误差=014=14
  2. 计算梯度:
    ∂ J ∂ w 1 = 1 m ∑ i = 1 m ( f w , b ( x ( i ) ) − y ( i ) ) ⋅ x 1 ( i ) ∂ J ∂ w 2 = 1 m ∑ i = 1 m ( f w , b ( x ( i ) ) − y ( i ) ) ⋅ x 2 ( i ) ∂ J ∂ b = 1 m ∑ i = 1 m ( f w , b ( x ( i ) ) − y ( i ) ) \frac{\partial J}{\partial w_1} = \frac{1}{m} \sum_{i=1}^{m} (f_{w,b}(x^{(i)}) - y^{(i)}) \cdot x_1^{(i)} \\ \frac{\partial J}{\partial w_2} = \frac{1}{m} \sum_{i=1}^{m} (f_{w,b}(x^{(i)}) - y^{(i)}) \cdot x_2^{(i)} \\ \frac{\partial J}{\partial b} = \frac{1}{m} \sum_{i=1}^{m} (f_{w,b}(x^{(i)}) - y^{(i)}) w1J=m1i=1m(fw,b(x(i))y(i))x1(i)w2J=m1i=1m(fw,b(x(i))y(i))x2(i)bJ=m1i=1m(fw,b(x(i))y(i))

    我们计算每个参数的梯度:

    • 对于 w 1 w_1 w1:
      ∂ J ∂ w 1 = 1 4 [ ( − 5 ) ⋅ 1 + ( − 8 ) ⋅ 2 + ( − 11 ) ⋅ 3 + ( − 14 ) ⋅ 4 ] = 1 4 ( − 5 − 16 − 33 − 56 ) = 1 4 ( − 110 ) = − 27.5 \frac{\partial J}{\partial w_1} = \frac{1}{4} [(-5) \cdot 1 + (-8) \cdot 2 + (-11) \cdot 3 + (-14) \cdot 4] \\ = \frac{1}{4} (-5 - 16 - 33 - 56) \\ = \frac{1}{4} (-110) \\ = -27.5 w1J=41[(5)1+(8)2+(11)3+(14)4]=41(5163356)=41(110)=27.5
    • 对于 w 2 w_2 w2:
      ∂ J ∂ w 2 = 1 4 [ ( − 5 ) ⋅ 2 + ( − 8 ) ⋅ 3 + ( − 11 ) ⋅ 4 + ( − 14 ) ⋅ 5 ] = 1 4 ( − 10 − 24 − 44 − 70 ) = 1 4 ( − 148 ) = − 37 \frac{\partial J}{\partial w_2} = \frac{1}{4} [(-5) \cdot 2 + (-8) \cdot 3 + (-11) \cdot 4 + (-14) \cdot 5] \\ = \frac{1}{4} (-10 - 24 - 44 - 70) \\ = \frac{1}{4} (-148) \\ = -37 w2J=41[(5)2+(8)3+(11)4+(14)5]=41(10244470)=41(148)=37
    • 对于 b b b:
      ∂ J ∂ b = 1 4 ( − 5 − 8 − 11 − 14 ) = 1 4 ( − 38 ) = − 9.5 \frac{\partial J}{\partial b} = \frac{1}{4} (-5 - 8 - 11 - 14) \\ = \frac{1}{4} (-38) \\ = -9.5 bJ=41(581114)=41(38)=9.5
  3. 更新参数:
    w 1 = w 1 − α ∂ J ∂ w 1 = 0 − 0.01 ( − 27.5 ) = 0.275 w 2 = w 2 − α ∂ J ∂ w 2 = 0 − 0.01 ( − 37 ) = 0.37 b = b − α ∂ J ∂ b = 0 − 0.01 ( − 9.5 ) = 0.095 w_1 = w_1 - \alpha \frac{\partial J}{\partial w_1} = 0 - 0.01 (-27.5) = 0.275 \\ w_2 = w_2 - \alpha \frac{\partial J}{\partial w_2} = 0 - 0.01 (-37) = 0.37 \\ b = b - \alpha \frac{\partial J}{\partial b} = 0 - 0.01 (-9.5) = 0.095 w1=w1αw1J=00.01(27.5)=0.275w2=w2αw2J=00.01(37)=0.37b=bαbJ=00.01(9.5)=0.095

第二次迭代

重复上述步骤,以更新后的参数 w 1 w_1 w1 w 2 w_2 w2 b b b继续计算新的梯度,并更新参数。以下是简略的计算过程:

  1. 计算预测值和误差:

    • 对于第一个样本 (1, 2, 5):
      f w , b ( x ( 1 ) ) = 0.275 ⋅ 1 + 0.37 ⋅ 2 + 0.095 = 1.11 误差 = 1.11 − 5 = − 3.89 f_{w,b}(x^{(1)}) = 0.275 \cdot 1 + 0.37 \cdot 2 + 0.095 = 1.11 \\ \text{误差} = 1.11 - 5 = -3.89 fw,b(x(1))=0.2751+0.372+0.095=1.11误差=1.115=3.89
    • 其他样本类似计算。
  2. 计算梯度:

    • 对于 w 1 w_1 w1:
      ∂ J ∂ w 1 ≈ − 21.23 \frac{\partial J}{\partial w_1} \approx -21.23 w1J21.23
    • 对于 w 2 w_2 w2:
      ∂ J ∂ w 2 ≈ − 28.74 \frac{\partial J}{\partial w_2} \approx -28.74 w2J28.74
    • 对于 b b b:
      ∂ J ∂ b ≈ − 6.83 \frac{\partial J}{\partial b} \approx -6.83 bJ6.83
  3. 更新参数:
    w 1 = 0.275 − 0.01 ( − 21.23 ) = 0.4873 w 2 = 0.37 − 0.01 ( − 28.74 ) = 0.6574 b = 0.095 − 0.01 ( − 6.83 ) = 0.1633 w_1 = 0.275 - 0.01 (-21.23) = 0.4873 \\ w_2 = 0.37 - 0.01 (-28.74) = 0.6574 \\ b = 0.095 - 0.01 (-6.83) = 0.1633 w1=0.2750.01(21.23)=0.4873w2=0.370.01(28.74)=0.6574b=0.0950.01(6.83)=0.1633

代码实现

def compute_gradient(X, y, w, b):
    m, n = X.shape
    dj_dw = np.zeros(n)
    dj_db = 0.0
    
    for i in range(m):
        error = (np.dot(X[i], w) + b) - y[i]
        for j in range(n):
            dj_dw[j] += error * X[i][j]
        dj_db += error
    
    dj_dw /= m
    dj_db /= m
    
    return dj_dw, dj_db

def gradient_descent(X, y, w, b, alpha, num_iters):
    for i in range(num_iters):
        dj_dw, dj_db = compute_gradient(X, y, w, b)
        w -= alpha * dj_dw
        b -= alpha * dj_db
    
    return w, b

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总结

通过以上的迭代过程,我们逐步更新参数 w 1 w_1 w1 w 2 w_2 w2 b b b,使得模型的预测值更加接近目标值。实际中,这个过程通常会重复多次,直到参数收敛。

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