利用Python爬取小说（附源码）_python爬小说代码

用30行代码爬取某小说网站上的一篇小说

一、导入模块

import requests
from lxml import etree
import time
1
2
3

二、获取网站的响应信息，并以text打印

url = 'https://www.biquge365.net/newbook/33411/'
head = {
    'Referer': 'https://www.biquge365.net/book/33411/',
    'users-agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/112.0.0.0 Safari/537.36 Edg/112.0.1722.39'
}
response = requests.get(url,headers = head,verify = False)
# print(response.text)
html = etree.HTML(response.text)
1
2
3
4
5
6
7
8

三、获取小说的标题及小说目录的href

#[0]列表的第0位
novel_name = html.xpath('/html/body/div[1]/div[3]/div[1]/h1/text()')[0]      
# print(novel_name)
novel_directory = html.xpath('/html/body/div[1]/div[4]/ul/li[*]/a/@href')
# print(novel_directory)
#访问太快易报错，设置休眠时间
time.sleep(5)
1
2
3
4
5
6
7

四、用for循环遍列小说目录，并获取小说正文

for i in novel_directory:
    com_url = 'https://www.biquge365.net'+i
    # print(com_url)
    response2 = requests.get(com_url,headers=head)
    html2 = etree.HTML(response2.text)
    novel_chapter = html2.xpath('//*[@id="neirong"]/h1/text()')[0]
    # print(novel_chapter)
    novel_content = '\n'.join(html2.xpath('//*[@id="txt"]/text()'))
    # print(novel_content)
1
2
3
4
5
6
7
8
9

五、保存小说

    # 'w'每次写入文件时会把上一次文件中内容清空，'a'追加内容，不会覆盖前面的内容
    with open('D:\\小说\\'+novel_chapter+'.txt','w',encoding='utf-8') as file:
        file.write(novel_chapter+'\n'+novel_content+'\n')
        file.close()
        print("下载成功"+novel_chapter)
1
2
3
4
5

六、下载成功展示

七、保存在电脑上的形式

八、效果展示

文章对你有帮助的话，麻烦点个赞吧！