赞
踩
数据操纵语言: 当添加, 更新或者删除数据库中的数据时, 需要使用DML语句. DML依据的一个集合构成了一个被称为事务的逻辑单元.
当完成下面操作时, DML语句被执行:
insert into table[(column [,column...])]
values (value[, value...]);
该语法一次只能插入一行
示例: 向departments表中添加一条数据.
Department_id=280
department_name=Teaching
Manager_id=180
location_id=2000
-- 添加语句, 注意, 必须提交事务, 不然数据会添加到临时的表空间中, 关闭数据库再打开, 仍然没有这个数据
SQL> insert into departments(department_id, department_name, manager_id, location_id)
2 values(280, 'Teaching', 180, 2000);
1 row inserted
-- 提交事务
SQL> commit;
Commit complete
示例: 向表中添加一条数据
department_id=290
department_name=development
manager_id=149
location_id=2000
-- 添加语句, 添加时候的添加顺序必须和建表时候的数据顺序一致
SQL> insert into departments values(290, 'development', 149, 2000);
1 row inserted
-- 提交事务
SQL> commit;
Commit complete
直接省略插入的列
示例: 插入一条数据
SQL> insert into departments(department_id, department_name) values(300, 'A');
1 row inserted
SQL> commit;
Commit complete
SQL> select * from departments where department_id = 300;
DEPARTMENT_ID DEPARTMENT_NAME MANAGER_ID LOCATION_ID
------------- ------------------------------ ---------- -----------
300 A
手动插入null
示例
SQL> insert into departments values(310, 'B', null, null);
1 row inserted
SQL> commit;
Commit complete
SQL> select * from departments where department_id = 310;
DEPARTMENT_ID DEPARTMENT_NAME MANAGER_ID LOCATION_ID
------------- ------------------------------ ---------- -----------
310 B
示例: 向employees表中插入一条数据
SQL> insert into employees(employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)
2 values (300, 'JingJing', 'Wang', 'asdf', null, sysdate, 'IT_PROG', 10000, null, 201, 290);
1 row inserted
SQL> commit;
Commit complete
SQL> select * from employees where employee_id = 300;
EMPLOYEE_ID FIRST_NAME LAST_NAME EMAIL PHONE_NUMBER HIRE_DATE JOB_ID SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID
----------- -------------------- ------------------------- ------------------------- -------------------- ----------- ---------- ---------- -------------- ---------- -------------
300 JingJing Wang asdf 2019/7/31 2 IT_PROG 10000.00 201 290
示例
SQL> insert into employees(employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)
2 values (301, 'JingJing', 'Wang', 'asdff', null, '01/3月/2019', 'IT_PROG', 10000, null, 201, 290);
1 row inserted
SQL> commit;
Commit complete
SQL> select * from employees where employee_id = 301;
EMPLOYEE_ID FIRST_NAME LAST_NAME EMAIL PHONE_NUMBER HIRE_DATE JOB_ID SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID
----------- -------------------- ------------------------- ------------------------- -------------------- ----------- ---------- ---------- -------------- ---------- -------------
301 JingJing Wang asdff 2019/3/1 IT_PROG 10000.00 201 290
示例
insert into employees(employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)
values (302, 'JingJing', 'Wang', 'asdfff', null, to_date('2019-07-31', 'yyyy-mm-dd'), 'IT_PROG', 10000, null, 201, 290);
SQL> commit;
Commit complete
SQL> select * from employees where employee_id = 302;
EMPLOYEE_ID FIRST_NAME LAST_NAME EMAIL PHONE_NUMBER HIRE_DATE JOB_ID SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID
----------- -------------------- ------------------------- ------------------------- -------------------- ----------- ---------- ---------- -------------- ---------- -------------
302 JingJing Wang asdfff 2019/7/31 IT_PROG 10000.00 201 290
create table EMP(
id number not null,
name varchar2(50),
salary number(8,2),
commission number(2,2)
)
将employees表中的job_id中含有REP的工作岗位的数据插入到emp表中
insert into emp select employee_id, last_name, salary, commission_pct from employees where job_id like '%REP%';
insert into emp values(302, 'Old2', default, null);
如果不指定列来插入, 没有默认值的会插入null值, 有默认值的会插入default值
update table
set column=value[, column=value,...]
[where condition];
示例: 更新emp表中的id为170的数据, 将名字修改为OLDLU;
SQL> select * from emp where id = 170;
ID NAME SALARY COMMISSION
---------- -------------------------------------------------- ---------- ----------
170 Fox 9600.00 0.20
SQL> update emp e set e.name = 'oldlu' where e.id = 170;
1 row updated
SQL> select * from emp where id = 170;
ID NAME SALARY COMMISSION
---------- -------------------------------------------------- ---------- ----------
170 oldlu 9600.00 0.20
示例: 更新emp表中的雇员165的薪水, 使其和雇员156相同
SQL> update emp e set e.salary = (select salary from emp where id = 156) where id = 165;
SQL> select id, salary from emp where id in (156, 165);
ID SALARY
---------- ----------
156 10000.00
165 10000.00
delete [from] table
[where condition];
示例: 删除emp表中id为302的雇员
SQL> select * from emp where id = 302;
ID NAME SALARY COMMISSION
---------- -------------------------------------------------- ---------- ----------
302 Wang 10000.00
302 Old2 300.00
SQL> delete from emp where id = 302;
2 rows deleted
SQL> commit;
Commit complete
示例: 删除emp表中薪水与IT_PROG岗位相同的薪水
SQL> select distinct salary from employees where job_id = 'IT_PROG';
SALARY
----------
9000.00
10000.00
4800.00
4200.00
6000.00
SQL> delete from emp where salary in (select distinct salary from employees where job_id = 'IT_PROG');
8 rows deleted
delete emp;
Copyright © 2003-2013 www.wpsshop.cn 版权所有,并保留所有权利。