Python课后作业 3. 文本分析与加密 ---- （第七次作业）_python123文本分析与加密

---

前引

---

原本我认为这道题会很难
其实之后做完才发现并没有那么难…
没什么思路 会点python的应该都看得懂我的代码
代码很直白 不拐弯抹角
就这样了

---

原题题目

---

---

代码实现

def encrypating(character,n):
    if character.islower():temp = ord('a');character = chr(temp+(ord(character)-temp+n)%26)
    else:temp = ord('A');character = chr(temp+(ord(character)-temp+n)%26)
    return character

l = list(str(input()));secret = 0
for i in l:
    secret = (secret + ord(i))%26

f = open("mayun.txt","r")
content = f.readlines()
upperchr = lowerchr = num = space = others = words = 0

for line in content:
    for i in line:
        if i.isupper():upperchr+=1
        elif i.islower():lowerchr+=1
        elif i.isspace():space+=1
        elif i.isdigit():num+=1
        else:others+=1
    str = line.replace('.', '')
    str = str.replace(',', '')
    str = str.replace("'", '')
    l = list(str.split(' '))
    words+=len(l)
print("%d %d %d %d %d"%(upperchr,lowerchr,num,space,others))
print("%d words in all"% words)
print("%d"% secret)

for line in content:
    ret = ""
    for char in line:
        if char.isalpha():ret += encrypating(char,secret)
        elif char != '\n':ret += char
    print(ret)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35

---

提交结果