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A. Nezzar and Colorful Balls_nezzar has nn balls, numbered with integers 1, 2,

nezzar has nn balls, numbered with integers 1, 2, \ldots, n1,2,…,n . number

time limit per test

1 second

memory limit per test

512 megabytes

input

standard input

output

standard output

Nezzar has nn balls, numbered with integers 1,2,…,n1,2,…,n. Numbers a1,a2,…,ana1,a2,…,an are written on them, respectively. Numbers on those balls form a non-decreasing sequence, which means that ai≤ai+1ai≤ai+1 for all 1≤i<n1≤i<n.

Nezzar wants to color the balls using the minimum number of colors, such that the following holds.

  • For any color, numbers on balls will form a strictly increasing sequence if he keeps balls with this chosen color and discards all other balls.

Note that a sequence with the length at most 11 is considered as a strictly increasing sequence.

Please help Nezzar determine the minimum number of colors.

Input

The first line contains a single integer tt (1≤t≤1001≤t≤100) — the number of testcases.

The first line of each test case contains a single integer nn (1≤n≤1001≤n≤100).

The second line of each test case contains nn integers a1,a2,…,ana1,a2,…,an (1≤ai≤n1≤ai≤n). It is guaranteed that a1≤a2≤…≤ana1≤a2≤…≤an.

Output

For each test case, output the minimum number of colors Nezzar can use.

Example

input

Copy

5
6
1 1 1 2 3 4
5
1 1 2 2 3
4
2 2 2 2
3
1 2 3
1
1

output

Copy

3
2
4
1
1

Note

Let's match each color with some numbers. Then:

In the first test case, one optimal color assignment is [1,2,3,3,2,1][1,2,3,3,2,1].

In the second test case, one optimal color assignment is [1,2,1,2,1][1,2,1,2,1].

 

解题说明:水题,统计数列中出现相同数字个数最多的那个即可。

  1. #include<stdio.h>
  2. int main()
  3. {
  4. int t;
  5. scanf("%d", &t);
  6. while (t--)
  7. {
  8. int i, n, a[102], c = 1, max = 1;
  9. scanf("%d", &n);
  10. for (i = 0; i<n; i++)
  11. {
  12. scanf("%d", &a[i]);
  13. }
  14. for (i = 0; i<n - 1; i++)
  15. {
  16. if (a[i] == a[i + 1])
  17. {
  18. c++;
  19. }
  20. else
  21. {
  22. c = 1;
  23. }
  24. if (c > max)
  25. {
  26. max = c;
  27. }
  28. }
  29. printf("%d\n", max);
  30. }
  31. return 0;
  32. }

 

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