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python如何设置窗口保持显示_让pythonthurtle窗口显示图形并保持打开状态

python turtle继续显示画面方法显示

我为您纠正了几个错误;我在注释中添加了解释:import turtle

hexagons_count = 0

my_turtle = turtle.Turtle() # x is not a good name for a Turtle object

# my_turtle.speed(.25) # see @cdlane comment reported in a note under.

def draw_hexagon(): # use explicit names respecting python conventions (no camel case)

global hexagons_count # need global to modify the variable in the function scope

for idx in range(24): # use different dummy variable names in your loops

for jdx in range(6): # use different dummy variable names in your loops

my_turtle.forward(100)

my_turtle.left(60)

hexagons_count += 1

my_turtle.left(15)

print(hexagons_count)

draw_hexagon() # need parenthesis to call the function

turtle.exitonclick() # this to exit cleanly

{a1}Note: I know you simply copied it from the OP but my_turtle.speed(.25)

doesn't make sense as the argument should be an int from 0 to 10 or a

string like 'slow', 'fastest', etc. I especially don't understand why

beginners with turtle code that isn't working call turtle.speed() at

all -- it seems to me a function to be tweaked after everything is

working. @cdlane

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