赞
踩
hashCode()获取哈希码(散列码),返回值为int。Object中hashCode的源码如下
/** * Returns a hash code value for the object. This method is * supported for the benefit of hash tables such as those provided by * {@link java.util.HashMap}. * <p> * The general contract of {@code hashCode} is: * <ul> * <li>Whenever it is invoked on the same object more than once during * an execution of a Java application, the {@code hashCode} method * must consistently return the same integer, provided no information * used in {@code equals} comparisons on the object is modified. * This integer need not remain consistent from one execution of an * application to another execution of the same application. * <li>If two objects are equal according to the {@code equals(Object)} * method, then calling the {@code hashCode} method on each of * the two objects must produce the same integer result. * <li>It is <em>not</em> required that if two objects are unequal * according to the {@link java.lang.Object#equals(java.lang.Object)} * method, then calling the {@code hashCode} method on each of the * two objects must produce distinct integer results. However, the * programmer should be aware that producing distinct integer results * for unequal objects may improve the performance of hash tables. * </ul> * <p> * As much as is reasonably practical, the hashCode method defined by * class {@code Object} does return distinct integers for distinct * objects. (This is typically implemented by converting the internal * address of the object into an integer, but this implementation * technique is not required by the * Java™ programming language.) * * @return a hash code value for this object. * @see java.lang.Object#equals(java.lang.Object) * @see java.lang.System#identityHashCode */ public native int hashCode();
英文简单翻译一下
hashCode常规协定:
a.在 Java 应用程序执行期间,在同一对象上多次调用 hashCode 方法时,必须一致地返回相同的整数,前提是对象上 equals 比较中所用的信息没有被修改。从某一应用程序的一次执行到同一应用程序的另一次执行,该整数无需保持一致。
b.如果根据 equals(Object) 方法,两个对象是相等的,那么在两个对象中的每个对象上调用 hashCode 方法都必须生成相同的整数结果。
c.以下情况不是必需的:如果根据 equals(java.lang.Object) 方法,两个对象不相等,那么在两个对象中的任一对象上调用 hashCode 方法必定会生成不同的整数结果。但是,程序员应该知道,为不相等的对象生成不同整数结果可以提高哈希表的性能。
d.实际上,由 Object 类定义的 hashCode 方法确实会针对不同的对象返回不同的整数。(这一般是通过将该对象的内部地址转换成一个整数来实现的,但是 JavaTM 编程语言不需要这种实现技巧)
产生的哈希码能确定对象在哈希表中的索引位置,散列表中存储的是K-V,能根据k定位v
package cn.tedu.scalapackage; import java.util.HashSet; /** * @description: hash测试 * @author: zfh * @email: hst1406959716@163.com * @date: Created in 2021/6/11 22:46 * @modified By: * @version: 1.0 */ public class TestHash { private int num; public int getNum() { return num; } public void setNum(int num) { this.num = num; } @Override public int hashCode() { return num % 100; } // @Override // public boolean equals(Object o) { // if (this == o) {return true;} // if (o == null || getClass() != o.getClass()){ return false;} // // TestHash testHash = (TestHash) o; // // return num == testHash.num; // } public static void main(String[] args) { TestHash testHash1 = new TestHash(); testHash1.setNum(1001); TestHash testHash2 = new TestHash(); testHash2.setNum(1001); System.out.println(testHash1.hashCode() == testHash2.hashCode()); System.out.println(testHash1.equals(testHash2)); HashSet hashSet = new HashSet(); hashSet.add(testHash1); hashSet.add(testHash2); System.out.println(hashSet.size()); } }
以上代码若是只重写hashCode方法,hash等equals不等说明是2个不同对象;若是放开equals注释,则hash等equals等说明是同一对象
Copyright © 2003-2013 www.wpsshop.cn 版权所有,并保留所有权利。