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Bag Of Words(词袋)模型,是现在一种用于图像检索的一种方法。它最早用于对于文章内容的检索,原理是将文本看作是单词的集合,不考虑文档内的词的顺序关系和语法等。通过建立词典,对每个单词出现次数进行统计,以便得到文本内容的分类。
计算机视觉的专家将Bag-of-words方法应用于图像的检索中就有了Bag-of-features。
和Bag-of-words原理相似,若将文档对应一幅图像的话,那么文档内的词就是一个图像块的特征向量。一篇文档有若干个词构成,同样的,一幅图像由若干个图像块构成,而特征向量是图像块的一种表达方式。我们求得N幅图像中的若干个图像块的特征向量,然后用k-means算法把它们聚成k类,相当于我们的词袋里就有k个词,然后来了一幅图像,看它包含哪些词,若包含单词A,就把单词A的频数加1。
特征提取
学习 “视觉词典(visual vocabulary)”
针对输入图片对应的特征集,根据视觉词典进行量化
把输入图像,根据TF-IDF转化成视觉单词(visual words)的频率直方图
构造特征到图像的倒排表,通过倒排表快速索引相关图像
根据索引结果进行直方图匹配
TF-IDF理解
- import pickle
- from pcv.imagesearch import vocabulary
- from pcv.tools.imtools import get_imlist
- from pcv.localdescriptors import sift
-
- #获取图像列表
- imlist = get_imlist('WYS/')
- nbr_images = len(imlist)
- #获取特征列表
- featlist = [imlist[i][:-3]+'sift' for i in range(nbr_images)]
-
- #提取文件夹下图像的sift特征
- for i in range(nbr_images):
- sift.process_image(imlist[i], featlist[i])
-
- #生成词汇
- voc = vocabulary.Vocabulary('ukbenchtest')
- voc.train(featlist, 1000, 10)
- #保存词汇
- with open('WYS/vocabulary.pkl', 'wb') as f:
- pickle.dump(voc, f)
- print ('vocabulary is:', voc.name, voc.nbr_words)
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- import pickle
- from pcv.imagesearch import imagesearch
- from pcv.localdescriptors import sift
- import sqlite3
- from pcv.tools.imtools import get_imlist
-
-
- # 获取图像列表
- imlist = get_imlist(r'WYS')
- nbr_images = len(imlist)
- # 获取特征列表
- featlist = [imlist[i][:-3] + 'sift' for i in range(nbr_images)]
-
- # 载入词汇
- with open(r'WYS\vocabulary.pkl', 'rb') as f:
- voc = pickle.load(f)
- # 创建索引
- indx = imagesearch.Indexer('testImaAdd.db', voc)
- indx.create_tables()
- # 遍历所有的图像,并将它们的特征投影到词汇上
- for i in range(nbr_images)[:120]:
- locs, descr = sift.read_features_from_file(featlist[i])
- indx.add_to_index(imlist[i], descr)
- # 提交到数据库
- indx.db_commit()
- con = sqlite3.connect('testImaAdd.db')
- print(con.execute('select count (filename) from imlist').fetchone())
- print(con.execute('select * from imlist').fetchone())
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- import pickle
- from pcv.imagesearch import imagesearch
- from pcv.geometry import homography
- from pcv.tools.imtools import get_imlist
- from pcv.localdescriptors import sift
- import warnings
- warnings.filterwarnings("ignore")
-
- # load image list and vocabulary
- # 载入图像列表
- imlist = get_imlist(r'WYS')
- print(imlist)
- nbr_images = len(imlist)
- # 载入特征列表
- print(imlist[1][:-3] + 'sift')
- featlist = [imlist[i][:-3] + 'sift' for i in range(nbr_images)]
-
- # 载入词汇
- with open(r'WYS\vocabulary.pkl', 'rb') as f:
- voc = pickle.load(f, encoding='iso-8859-1')
-
- src = imagesearch.Searcher('testImaAdd.db', voc) # Searcher类读入图像的单词直方图执行查询
-
- # index of query image and number of results to return
- # 查询图像索引和查询返回的图像数
- q_ind = 3
- nbr_results = 10
-
- # regular query
- # 常规查询(按欧式距离对结果排序)
- res_reg = [w[1] for w in src.query(imlist[q_ind])[:nbr_results]] # 查询的结果
- print('top matches (regular):', res_reg)
-
- # load image features for query image
- # 载入查询图像特征进行匹配
- q_locs, q_descr = sift.read_features_from_file(featlist[q_ind])
- fp = homography.make_homog(q_locs[:, :2].T)
-
- # RANSAC model for homography fitting
- # 用单应性进行拟合建立RANSAC模型
- model = homography.RansacModel()
- rank = {}
- # load image features for result
- # 载入候选图像的特征
- for ndx in res_reg[1:]:
- locs, descr = sift.read_features_from_file(featlist[ndx]) # because 'ndx' is a rowid of the DB that starts at 1
- # get matches
- matches = sift.match(q_descr, descr)
- ind = matches.nonzero()[0]
- ind2 = matches[ind]
- tp = homography.make_homog(locs[:, :2].T)
- # compute homography, count inliers. if not enough matches return empty list
- # 计算单应性矩阵
- try:
- H, inliers = homography.H_from_ransac(fp[:, ind], tp[:, ind2], model, match_theshold=4)
- except:
- inliers = []
- # store inlier count
- rank[ndx] = len(inliers)
-
- # sort dictionary to get the most inliers first
- # 对字典进行排序,可以得到重排之后的查询结果
- sorted_rank = sorted(rank.items(), key=lambda t: t[1], reverse=True)
- res_geom = [res_reg[0]] + [s[0] for s in sorted_rank]
- print('top matches (homography):', res_geom)
-
- # 显示查询结果
- imagesearch.plot_results(src, res_reg[:6]) # 常规查询
- imagesearch.plot_results(src, res_geom[:6]) # 重排后的结果
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