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Given a square array of integers A, we want the minimum sum of a falling path through A.
A falling path starts at any element in the first row, and chooses one element from each row. The next row’s choice must be in a column that is different from the previous row’s column by at most one.
解题思路比较简单,一层层计算下来即可,见代码。
// An highlighted block class Solution: def minFallingPathSum(self, A): """ :type A: List[List[int]] :rtype: int """ for i in range(1, len(A)): for j in range(len(A[0])): if j-1>=0: topleft=A[i-1][j-1] else: topleft=float('inf') if j+1<len(A[0]): topright=A[i-1][j+1] else: topright=float('inf') A[i][j] += min(topleft, topright, A[i-1][j]) return min(A[-1])
https://leetcode.com/problems/minimum-falling-path-sum/discuss/221123/Very-Easy-to-Understand-Python-6-line-DP-with-no-extra-space-beats-90
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