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二分答案
class Solution { long long check(vector<int> time,long long k) { long long res=0; for(auto t:time) res += (long long)k/t; return res; } public: long long minimumTime(vector<int>& time, int totalTrips) { int n = time.size(); sort(time.begin(),time.end()); long long l=time[0] - 1,r=(long long)totalTrips*time[0]; while(l<r) { long long mid = l + r >> 1; if(check(time,mid) < (long long)totalTrips) l = mid + 1; else r = mid; } return l; } };
库函数min
class Solution { public: long long minimumTime(vector<int>& time, int totalTrips) { //内联函数 比外部函数快一倍 auto check = [&](long long x) -> bool { long long res=0; for(int t : time) { res += x/t; if(res >= totalTrips) return true; } return false; }; //求最小值 int min_t = ranges::min(time); long long l=min_t,r=(long long)totalTrips*min_t; while(l<r) { long long mid = l + r >> 1; //说明当前mid时res >= total if(check(mid)) r = mid; else l = mid + 1; } return r; } };
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