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一、实验目的
1、掌握串行口工作方式0的使用和用C51的编程方法;
2、掌握移位寄存器74HC164的工作原理;
3、掌握单片机驱动喇叭发声原理;
4、掌握定时计数器产生方波的编程方法;
二、实验设备与环境
硬件:DOFLY单片机实验仪;
软件:Keil uVision3开发环境。
三、实验内容
1、实验内容一
1.1、问题一:
使用74HC164的并行输出引脚接8支发光二极管,利用它的串入并出功能,把发光二极管从左向右轮流点亮,并反复循环。RXD(P3.0)接J11 A、B,TXD(P3.1)接J11 CLK,输出J12用8根杜邦线接发光二极管J9电路。原理图见图1:
1.2、问题一的代码:
- #include <reg51.h>
- #include <intrins.h>
- sbit P1_0 = P1^0;
- void delay();
- void main()
- {
- unsigned char i;
- SCON = 0x00;
- ES = 0;
- for (;;)
- {
- for (i = 0; i < 8;i++)
- {
- P1_0 = 0;
- SBUF = _cror_(0x80,i);
- while(!TI)
- {}
- P1_0 = 1;
- TI = 0;
- delay();
- }
- }
- }
- void delay()
- {
- int y;
- for(y=300;y>0;y--);
- }
2、实验内容二
2.1、问题二:
用定时器T1方式1来产生歌谱中各音符对应频率的方波,由P1.1输出驱动喇叭。实现有外部中断0时演奏乐曲“小星星”一次,有外部中断1时演奏乐曲“新年好”一次。控制节拍可通过调用延时子程序次数来实现(考虑外部中断和定时计数器中断的优先级),ULN2003为电流放大芯片,驱动喇叭。
把乐谱中的音符和相应的节拍变换为定时常数和延时常数,作为数据表格数组tab存放在存储器中。每演奏一个音符调用定时常数和延时常数,分别用以控制定时器产生方波的频率和该频率方波的持续时间。当延时时间到,再调用下一个音符的定时常数和延时常数。依次下去,就可自动演奏出乐曲。
实验原理图见图2,流程图见图3:
2.2、问题二的代码:
- #include <reg51.h>
- #include <intrins.h>
- void delay(int);
- code tab1[] = {0xFC,0x44,0x04,0xFC,0x44,0x04,0xFD,0x83,0x04,0xFD,0x83,0x04,0xFD,
- 0xC8,0x04,0xFD,0xC8,0x04,0xFD,0x83,0x04,0x00,0x00,0x04,0xFD,0x34,0x04,0xFD,
- 0x34,0x04,0xFD,0x09,0x04,0xFD,0x09,0x04,0xFC,0xAD,0x04,0xFC,0xAD,0x04,0xFC,
- 0x44,0x04,0x00,0x00,0x04,0xFF,0xFF};
- code tab2[] = {0xFC,0x4A,0x04,0xFC,0x4A,0x04,0xFC,0x4A,0x08,0xFB,0x00,0x08,0xFD,
- 0x08,0x04,0xFD,0x08,0x04,0xFD,0x08,0x08,0xFC,0x4A,0x08,0xFC,0x4A,0x04,0xFD,0x08,
- 0x04,0xFD,0x80,0x08,0xFD,0x80,0x08,0xFD,0x30,0x04,0xFD,0x08,0x04,0xFC,0xAE,0x08,
- 0x00,0x00,0x08,0xFF,0xFF};
- sbit P1_1 = P1^1;
- int H,L;
- void main()
- {
- EA = 1;
- ET1 = 1;
- EX0 = 1;
- EX1 = 1;
- PT1 = 1;
- TCON = 0x05;
- TMOD = 0x10;
- P1_1 = 1;
- while(1) ;
- }
-
- void star() interrupt 0
- {
- int t;
- int i;
- for (i = 0; i < 17;i++)
- {
- H = tab1[i*3];
- L = tab1[i*3 + 1];
- if (H == 0x00 && L == 0x00)
- TR1 = 0;
- else if (H == 0xFF && L == 0xFF)
- break ;
- else
- {
- TR1 = 1;
- TH1 = H;
- TL1 = L;
- }
- t = tab1[i * 3 + 2];
- delay(t);
- }
- }
- void new() interrupt 2
- {
- int t;
- int i;
- for (i = 0; i < 17;i++)
- {
- H = tab2[i*3];
- L = tab2[i*3 + 1];
- if (H == 0x00 && L == 0x00)
- TR1 = 0;
- else if (H == 0xFF && L == 0xFF)
- break ;
- else
- {
- TR1 = 1;
- TH1 = H;
- TL1 = L;
- }
- t = tab2[i * 3 + 2];
- delay(t);
- }
- }
- void rec() interrupt 3
- {
- P1_1 = !P1_1;
- TH1 = H;
- TL1 = L;
- }
- void delay(int n)
- {
- while (n--)
- {
- int i,j;
- for (i = 10; i > 0;i--)
- for(j = 625 ; j > 0;j--);
- }
- }
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