单向链表_set next

虽然链表有序，但是它是以节点形式存储的，位置不连续。每个节点存data和下一个节点的地址

链表分为有头节点的和没头节点的。

示例代码：
节点设置：

package single_link;
 
public class Node {
	private int num;
	private String name;
	private String nickname;
	private Node next;
	public Node(int num,String nickname,String name) {
		this.name=name;this.num=num;this.nickname=nickname;
	}
	public int getNum() {
		return num;
	}
	public void setNum(int num) {
		this.num = num;
	}
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public String getNickname() {
		return nickname;
	}
	public void setNickname(String nickname) {
		this.nickname = nickname;
	}
	
	public Node getNext() {
		return next;
	}
	public void setNext(Node next) {
		this.next = next;
	}
	public String toString() {
		return nickname+name;
	}
}

链表设置：
 

package single_link;
 
public class linked_list {
	private Node headNode=new Node(0,"","") ;
	//新建链表时加入元素，加到链表末尾
	public void add(Node newNode) {
		Node tmp=headNode;
		while (true) {
			if (tmp.getNext()==null) {
				break;
			} else {
				tmp=tmp.getNext();
			}
		}
		tmp.setNext(newNode);
	}
	//展示链表
	public void showList() {
		if (headNode==null) {
			System.out.println("null");
		}
		System.out.println(headNode);
		Node tmp=headNode;
		while (tmp.getNext()!=null) {
			System.out.println(tmp.getNext());
			tmp=tmp.getNext();
		}
	}
	//将一个节点以num的顺序加入到链表中
	public void insert(Node newNode) {
		Node tmp=headNode;
		while (tmp.getNum()<newNode.getNum()&&tmp.getNext()!=null) {
			if (tmp.getNext().getNum()>newNode.getNum()) {
				newNode.setNext(tmp.getNext());
				tmp.setNext(newNode);
				return;
			}else {
				tmp=tmp.getNext();
			}
		}
		tmp.setNext(newNode);
	}
	//修改某个编号
	public void modify(int num,String nickname,String name) {
		Node tmp=headNode;
		while (tmp!=null) {
			if (tmp.getNum()==num) {
				tmp.setNickname(nickname);
				tmp.setName(name);
				return;
			} else {
				tmp=tmp.getNext();
			}
		}
		System.out.println("查无此人");
	}
	//删除某个编号
	public void del(int num) {
		if (headNode.getNum()==num) {
			headNode=headNode.getNext();
			return;
		}
		Node tmp=headNode;
		while (tmp.getNext()!=null) {
			if (tmp.getNext().getNum()==num) {
				tmp.setNext(tmp.getNext().getNext());
				return;
			} else {
				tmp=tmp.getNext();
			}
		}
		System.out.println("查无此人");
	}
}