Codeforces Round #690 (Div. 3) C. Unique Number 暴力打表

You are given a positive number x. Find the smallest positive integer number that has the sum of digits equal to x and all digits are distinct (unique).

Input
The first line contains a single positive integer t (1≤t≤50) — the number of test cases in the test. Then t test cases follow.

Each test case consists of a single integer number x (1≤x≤50).

Output
Output t answers to the test cases:

if a positive integer number with the sum of digits equal to x and all digits are different exists, print the smallest such number;
otherwise print -1.
Example
inputCopy
4
1
5
15
50
outputCopy
1
5
69
-1
手动打表，循环匹配

#include<iostream>
#include<string>
#include<map>
#include<algorithm>
#include<memory.h>
#include<cmath>
using namespace std;
typedef long long ll;
const int maxn=1e5+5;
int a[maxn]={0,1,2,3,4,5,6,7,8,9,19,29,39,49,59,69,79,89,189,289,389,489,589,689,789,1789,2789,3789,4789,5789,6789,16789,26789,36789,46789,56789,156789,256789,356789,456789,1456789,2456789,3456789,13456789,23456789,123456789,-1,-1,-1,-1,-1,-1,-1,-1,-1};

void solve(){
	 int t;
    cin>>t;
    while(t--)
    {
        int n;
        cin>>n;
        cout<<a[n]<<endl;
    }
}
int main()
{
	ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
	solve();
	return 0;
}


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