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2018第九届蓝桥杯JAVA C组 第三题 字母阵列 题解_2018年java组c组第三题

2018年java组c组第三题

标题:字母阵列


仔细寻找,会发现:在下面的8x8的方阵中,隐藏着字母序列:"LANQIAO"。
SLANQIAO
ZOEXCCGB
MOAYWKHI
BCCIPLJQ
SLANQIAO
RSFWFNYA
XIFZVWAL
COAIQNAL

我们约定: 序列可以水平,垂直,或者是斜向;
并且走向不限(实际上就是有一共8种方向)。
上图中一共有4个满足要求的串。

下面有一个更大的(100x100)的字母方阵。
你能算出其中隐藏了多少个“LANQIAO”吗?

FOAIQNALWIKEGNICJWAOSXDHTHZPOLGYELORAUHOHCZIERPTOOJUITQJCFNIYYQHSBEABBQZPNGYQTCLSKZFCYWDGOAIADKLSNGJ
GSOZTQKCCSDWGUWAUOZKNILGVNLMCLXQVBJENIHIVLRPVVXXFTHQUXUAVZZOFFJHYLMGTLANQIAOQQILCDCJERJASNCTLYGRMHGF
TSDFYTLVIBHKLJVVJUDMKGJZGNNSTPVLCKTOFMUEUFSVQIAUVHNVFTGBDDARPKYNNCUOYUAZXQJNOEEYKLFRMOEMHUKJTPETHLES
FKVINSLWEVGAGMKVFVIUBMYOIAFHLVNKNTYKTZWVXQWRWIGPENFXYDTKRVPKRTHMGHVYOCLDCKMEKRLGEKBYUCLOLYPAKPFSOREH
KWPUOLOVMOFBIXYACWRDYBINTMPASPCEOKHXQIGBQQMCEOIVULIEOPFSCSIHENAJCVDPJDOIWIIULFDNOZOFVAMCABVGKAKCOZMG
XWMYRTAFGFOCNHLBGNGOXPJSTWLZUNNAGIRETGXFWAQSSJPFTQAXMTQWMZWYVEPQERKSWTSCHSQOOBGXAQTBCHOEGBDVKGWJIFTG
ZWWJEIISPLMXIMGHOOGDRZFTGNDDWDWMNUFWJYJGULPHNUFSAQNNIUVAAFZIAZKFXXNWCEABGJAUMGYEIEFVQXVHHHEDYUITRCQB
XZHDPZQTOBECJVBZLACVXACZEDYOGVAVQRNWEOWGRAQYUEUESTEDQTYJUTEFOOITSHDDZHONJGBRCWNEQLZUTBNQIADKNFIOMWZR
EBFKCVNLURZSNPOLTISRPDTNUMCDGKTYRGIOVEPTUTSBAWQKWWEUWIWHAANUZUADGZEATZOQICWFUJTWNZDBKLQNELWVTBNDLNFH
PESISEATZNCDFRMXBQUKBFTIGYSFCWVHPMSUSDKPSCOMVLDOHYQVFHAJKRDTAVLIMNZBZSMLMRTLRPSLAHXDBASDMWAAYBPYVJZF
SCCWYHLQOUKBMCEYENQNJXFOMOOJMTKDSHJJOHDKEGATFZHGWJJAZJROWHAZUFGEQKPYXLCAAXHHQBDALPYUDWZQHBASBBCFGQCQ
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POCKVEQXUAVHERIAQLGJHYOOVOMTXQFRTBFSETOZICPCHZHFBWNESVJJLSVSVOOGYYABFESWNWDNYBGBNAKRCFQMTCUMIFTESVIN
JCAULIQRYUMAMAOVVWSEUTMECXSDTONRMMROQUISYEURSAYNZUVOPXLIFBDOHPXMABBLEQZGLJXQJOEYYRRRCFTEZQAOIWKRJQDL
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SIKWLXQHKDFJVGBVXWDWJKUSFRQRTDJYQMNFOQQALHRLMHSDMCFLAOVKDMTKMTPVTLAZLYJNJXZCFRHHSDIXYUUSVIMIICLUJHFW
JHWUSMCFYHPIXHAPBBSHYDQCKVGQFTENLVERFVOVDCLSTQFUSEPUMTFODLZLYQXDOXAEPONIQWTDWSAWBNSZYACGSJQSHAUMIKXT
MVBNFXMFNPAYSODPXEAYNRKTEZJWMUACSIUYPIORUFPMXAOZZJPJXPFLNSKNIAMETMOVULZPQIJJIRCSYQXOEVRHCNACSBRHKYNW
KGKBTBHGWKVJYZCOVNSKUREKZEIWVLOHAMUAYKLUGHEUESICBZAHURNTJAECTHRNKSIJQFIPVZANSZYSPJWHPKHCAPEYWNXUYQSD
RRRFYQFIQSWYRQTSNGNUFOBMSLGAFWPJGYEHGASFKTJCCZPXFIQLSXNKNWCYVTETOAPCOZJNHEWOCCAWVDEZUQCLLAVUQJJTQCKJ
NMBKMUENVGXXVMQCLXPJDQIQCFWYADIFDSGINGZDJYHPUPXVRMWDIPJRWPNRYOFGYYPEAVKDEMLYRRRMNCRQXPTDSQIVKKGJWDEF
SBAEKIFZCKDOMIQKBDWVQGBYWPDIBOLQUGAQRXLJDAZMXVZXYSNWEWTNZKYREMBEUHOTFOCKEJSXCMUBCKXNGQXTQJRCRCLWJTOI
YXBFBIBRAAFNPKBLTSMCFERZURZNWHMOEHIHNQTBWXNPJGIDYDPRGEWACCBULJRACOFLANQIAOIHMYCNQHVKXSIGAMWAHUSNBBTD
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CITGTILGPGBHZMNWWHXEFPGDPJUVFBJKAQWACZHPRPJYCOLGZTBDCVHNRSUAJUQAWAPMQJDQIFPZQZEONWHIYKMXDZOMVETEFJRB
RDOTIDCFEESOKYPYCGQQKOGPMGJRITSVTKOKDSXLRLJRRHNFRFXCMDNQMCEGZFJWHZOAFBQXXPXNBSWTSUYPAWQRHAUGLNPBRSJT
HOWRIUGMOQTUYIHDWJRFBWWKWYKCICSVBVKTBIIWGFSVIFCTUKIHHUUISCOTEOYRWQXTAEBXQQOLLMOALNIYVCCHNSWIKHMYYNZO
OFRIYYXPPSRTPAYMUJSSDILKIZAYSEIOLANQIAOVKARDPGVFCSYBSNHAPGTIKLAWTTKOEADWRLAACAAFYTBTNSGFTYLYUHJXBMMA
NJFTMLUIBKDPWBXQOMBVQXCZOIREHRSZCSJOIVBXWQIBUTYBQNTZRVROHGOIZYAJWXLEATLOZJIKJMIHSLGSVTCXJWIOOGWSERRQ
DBQJNGBLRIYFIKHBEYOZQBOAGGNIZKFDHWXCFNJLBQXVLHIQNIBZSDLTTRERHNWCMLJCVBBGGAQTPUQHIRABXPQSYGSDVMBNNDFG
KPLFUYXHYGOCZPPXMWCZYNKCYBCRZVKFBHQXPGPBZFTTGEPQTJMOFHAYSQQZDMQECGXOXADYHNNXUKNBXZBYHBOULXNBJZKIZREF
LVHAMSNXJOCVRPVGJUWXFVOCUCLCZDXRPBBDRLRAVVNLOZWOHWMXYSNMXAKJYWYGILNGUJGIPKAUDVANZLFWKUWWUSQYBRCBVDIJ
QCXPLOTPPGXCUZOUSSTXHVMLHVMJTUSSOPLRKEBQSGWNGVHKANVZWYQHSHLIPWSYCPKTUKPMWPLVFLLAHXZQANFXHFNYHIQVIOYN
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GKGWUCJXUKAEHLRLNDFUQPSJAZTVJRXWXQVBMRJXULEMJJPDCVTOWVFDBVLSBHZRRQUVMUQYKTJCLSGGHGCPHPHMWYAECLJIZUWV
QQNKPQRJMSOCEAYDNKPHVEGKAGCKAPDXTGVXULHUXHJPDXCSKQTCJENVTZTMRUENCSWHBEORALSREBWAJEMQDXMRKGHJGICDHKHY
YNSDSWDRLBBFUFVVICMGUCGBSVDLJNXGKXNFGVLKAVBJRRRUHKRXTPBJAKIEBAVMDIOJLIUDABCGNPNJIYBCXMOOWKRPHPYSWRDC
BORWTNBISSLTVKBRTLWKRNCEDCNEGCIYJIPDICFAVNOISYAHWBLGMNFKXZYTTWJOBEPNMSJEJMHXVPGOJOLQQQVXFGEULANQIAOD
OQETOJHCZXGTUKIWGMEVVMXCURISUOFQSAWZWDMZWVYHZMPEIMWKJDGERODVVUXYRTYLCRGYQQOIOFZSSZRAIESWBQOAIQNALJNR
HEYWHPLLPCUEOCBAOWGAYEJZQJHLVNMVQNSQQGGUBOIMDPFLOVSQGBLYAMBRYJDVOXOQINLJAVYALAKHPKOYNKGXIISSJNGKHYMS
IQVRYKXCUFIRNENEXFJTMOTJWYXSMTDHHPRHWIXETWVVIXZELKLLWRWQYGBCGJNYSUQEFCOUDNIJMLJNLAWSYJGULKBCFPYVSSMW
WQHGWRQFWFOTGPBBSJBDUKOMBXNRPIMCGPGVZFADWTBVIEMVTBXVAFQDDMJALCOMZTXUFFKBQQZDFAMTFWEXTHBKNWRLUVITQXLN
OPPJQKNGHWWPENVQIABJCQNKXNPWOWRFEOKQPQLANQIAORGGOLAYCEGZBHZVLPBERWYIJNJUNXKULUQOJLTNRDZDEYWEMYCHJLLB
LJISOAQLXJEFXVTOZSICOLQIJEXUANJWIFSIMGUQWHBXUDWOEILYFUZTGDZDSPLZPDPXBLFAXLEFQFEPDSJQWEQMXKKHCXHMSATM
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PDOFSCKKJJTRYRWGLEZODQTJSIMXIAOLNMLPHBAYLPTTLPYWILSEIIQVSXNHIJEORVCNJHYXRBIZZJTADGMRTSXVRXYGVQQNUEIC
IHNJOQXUXTXFPALCHOELNVMWDWQTEARUKPIFWXJSMWZLMNLAODUTKNZDYRFRLGBLIBGIBXJBOYMLYLANQIAORORYKSJPOOOAMVRN
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PYIANSGMNKBCDPHWDUPKICQEUDNZPNGRUJYSZIRLXGXXITAFBCANGDLVAQLDPVTJNSAUZMBBNOBBOERSHQIOLBVTSPPJKVCMXUBS
IKMDIYSNCJZKJKJQMTIKEPRUNAHJUSWJHSLWIVWHYAYLOIOGSZVWKQWXZDBPHWZRAIPMXDJHBIISVJWVEVZAEGAKCYYMNZARBZPC
DLDFVQDFDMVHYVOWEKMFKWUXLTPWIVKPRZZXOLMDAPAIQEKJHCHYAGJDBOFWDGNEGQGOOKWSKLTLREMGGTVJFHAIBCQKNZVRCZYS
FBQASGNCCBBGNKJHCDBTGBIIWKMPHDABKEWDEPYEAVKNMPATUZZUOEHGUGAZNECSGUCIIJPMMRAMTVADMTCRJCBWDLWWFNFOWMVZ
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CURAGWXMLYBSIZLAXFONZZMQMRNNSRQKRHQGFGZUTLONAYRKSSOWAMKZBSGOOYQDPTBHGPBNQEDCZHRTOXREOFJEKJVIZXZBCJPN
KGYBZTZRKOGBETJRUWRNUCIFKIMCZGYTZLCZYGCGKVZRJIFZQIQPTCPPUHYWIXBOFFGSGSAIMNGKKUUROAVNJUQQNSWJRZIZEHAF
DDAOBVCPOVODVJFLSNPJXHWQBHILWZAHQQMTQASNADZLZNXJLJMFCOUWOZJCMVVTYCKTUBABWLCEBNYWAMOLNBQQYBRUJCQCZALE
TVVRPMYFIKINHIUEJBDLTCUMMUWICIUVCZNIQIUEWVAHLANQIAONMEYJWPDAFXVNOSOFDOCESSLGZPTJINBUAFWWWMPTYALZIGVD
DCZGKILMBFXIQQFEKJBIUDEMIFCANVGNYZAYSQFMNNQFEPZFUUVGTBKSMDXITBLANQIAOQUKTPNYPOWSQQYWWMJHSDYVFDJYXBAF
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SYSFUAJFKIPUJVQSZRWQCJYAUMLDDNOKODDXIEQIFLANQIAOZFUNKUBVDBLMJOAUTVCZVLKJRQIORQPGAVCEYVNYUZHXILHERYEC
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WSDAUGUTVWCVHEMOIRJJGTANUWTSAIXXEVZTBDHPGSRHHVWCDZVZYRJTLONIJVXEATHQXOUKBIGZONFRSZIOGWNTYAJYLQCGEOWY

 

请提交一个整数,不要填写任何多余的内容。

解题思路:我是用C语言解的纯暴力,JAVA解法也一样。先将这堆字母存进数组,然后遍历,看见‘L’就找他周围的‘A’,‘N’,‘Q’,‘I’,‘A’,‘O’。找到O就结果s++,最后输出。为了验证,我加了个标记数组f[100][100]。找到O就将LANQIAO全部赋值为1最后输出很可观

答案是:41。

  1. #include<stdio.h>
  2. char a[100][100];
  3. int f[100][100]={0};
  4. int main(){
  5. for(int i=0;i<100;i++)
  6. scanf("%s",a[i]);
  7. int s=0;
  8. for(int i=0;i<100;i++){
  9. for(int j=0;j<100;j++){
  10. if(a[i][j]=='L'&&i+6<100&&j+6<100){
  11. if(a[i+1][j+1]=='A'){
  12. if(a[i+2][j+2]=='N'){
  13. if(a[i+3][j+3]=='Q'){
  14. if(a[i+4][j+4]=='I'){
  15. if(a[i+5][j+5]=='A'){
  16. if(a[i+6][j+6]=='O'){
  17. f[i][j]=1;
  18. f[i+1][j+1]=1;
  19. f[i+2][j+2]=1;
  20. f[i+3][j+3]=1;
  21. f[i+4][j+4]=1;
  22. f[i+5][j+5]=1;
  23. f[i+6][j+6]=1;
  24. s++;
  25. }
  26. }
  27. }
  28. }
  29. }
  30. }
  31. }
  32. if(a[i][j]=='L'&&i+6<100&&j-6>=0){
  33. if(a[i+1][j-1]=='A'){
  34. if(a[i+2][j-2]=='N'){
  35. if(a[i+3][j-3]=='Q'){
  36. if(a[i+4][j-4]=='I'){
  37. if(a[i+5][j-5]=='A'){
  38. if(a[i+6][j-6]=='O'){
  39. f[i][j]=1;
  40. f[i+1][j-1]=1;
  41. f[i+2][j-2]=1;
  42. f[i+3][j-3]=1;
  43. f[i+4][j-4]=1;
  44. f[i+5][j-5]=1;
  45. f[i+6][j-6]=1;
  46. s++;
  47. }
  48. }
  49. }
  50. }
  51. }
  52. }
  53. }
  54. if(a[i][j]=='L'&&i-6>=0&&j+6<100){
  55. if(a[i-1][j+1]=='A'){
  56. if(a[i-2][j+2]=='N'){
  57. if(a[i-3][j+3]=='Q'){
  58. if(a[i-4][j+4]=='I'){
  59. if(a[i-5][j+5]=='A'){
  60. if(a[i-6][j+6]=='O'){
  61. f[i][j]=1;
  62. f[i-1][j+1]=1;
  63. f[i-2][j+2]=1;
  64. f[i-3][j+3]=1;
  65. f[i-4][j+4]=1;
  66. f[i-5][j+5]=1;
  67. f[i-6][j+6]=1;
  68. s++;
  69. }
  70. }
  71. }
  72. }
  73. }
  74. }
  75. }
  76. if(a[i][j]=='L'&&i-6>=0&&j-6>=0){
  77. if(a[i-1][j-1]=='A'){
  78. if(a[i-2][j-2]=='N'){
  79. if(a[i-3][j-3]=='Q'){
  80. if(a[i-4][j-4]=='I'){
  81. if(a[i-5][j-5]=='A'){
  82. if(a[i-6][j-6]=='O'){
  83. f[i][j]=1;
  84. f[i-1][j-1]=1;
  85. f[i-2][j-2]=1;
  86. f[i-3][j-3]=1;
  87. f[i-4][j-4]=1;
  88. f[i-5][j-5]=1;
  89. f[i-6][j-6]=1;
  90. s++;
  91. }
  92. }
  93. }
  94. }
  95. }
  96. }
  97. }
  98. if(a[i][j]=='L'&&j-6>=0){
  99. if(a[i][j-1]=='A'){
  100. if(a[i][j-2]=='N'){
  101. if(a[i][j-3]=='Q'){
  102. if(a[i][j-4]=='I'){
  103. if(a[i][j-5]=='A'){
  104. if(a[i][j-6]=='O'){
  105. f[i][j]=1;
  106. f[i][j-1]=1;
  107. f[i][j-2]=1;
  108. f[i][j-3]=1;
  109. f[i][j-4]=1;
  110. f[i][j-5]=1;
  111. f[i][j-6]=1;
  112. s++;
  113. }
  114. }
  115. }
  116. }
  117. }
  118. }
  119. }
  120. if(a[i][j]=='L'&&j+6<100){
  121. if(a[i][j+1]=='A'){
  122. if(a[i][j+2]=='N'){
  123. if(a[i][j+3]=='Q'){
  124. if(a[i][j+4]=='I'){
  125. if(a[i][j+5]=='A'){
  126. if(a[i][j+6]=='O'){
  127. f[i][j]=1;
  128. f[i][j+1]=1;
  129. f[i][j+2]=1;
  130. f[i][j+3]=1;
  131. f[i][j+4]=1;
  132. f[i][j+5]=1;
  133. f[i][j+6]=1;
  134. s++;
  135. }
  136. }
  137. }
  138. }
  139. }
  140. }
  141. }
  142. if(a[i][j]=='L'&&i-6>=0){
  143. if(a[i-1][j]=='A'){
  144. if(a[i-2][j]=='N'){
  145. if(a[i-3][j]=='Q'){
  146. if(a[i-4][j]=='I'){
  147. if(a[i-5][j]=='A'){
  148. if(a[i-6][j]=='O'){
  149. f[i][j]=1;
  150. f[i-1][j]=1;
  151. f[i-2][j]=1;
  152. f[i-3][j]=1;
  153. f[i-4][j]=1;
  154. f[i-5][j]=1;
  155. f[i-6][j]=1;
  156. s++;
  157. }
  158. }
  159. }
  160. }
  161. }
  162. }
  163. }
  164. if(a[i][j]=='L'&&i+6<100){
  165. if(a[i+1][j]=='A'){
  166. if(a[i+2][j]=='N'){
  167. if(a[i+3][j]=='Q'){
  168. if(a[i+4][j]=='I'){
  169. if(a[i+5][j]=='A'){
  170. if(a[i+6][j]=='O'){
  171. f[i][j]=1;
  172. f[i+1][j]=1;
  173. f[i+2][j]=1;
  174. f[i+3][j]=1;
  175. f[i+4][j]=1;
  176. f[i+5][j]=1;
  177. f[i+6][j]=1;
  178. s++;
  179. }
  180. }
  181. }
  182. }
  183. }
  184. }
  185. }
  186. }
  187. }
  188. for(int i=0;i<100;i++){
  189. for(int j=0;j<100;j++){
  190. if(f[i][j]==1)
  191. printf("%c",a[i][j]);
  192. else
  193. printf(" ");
  194. }
  195. printf("\n");
  196. }
  197. printf("\n\n%d",s);
  198. return 0;
  199. }

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