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2024年最新【算法学习】剑指 Offer 64(2)，2024年最新vue总结来了

作者：黑客灵魂 | 2024-08-20 11:57:12

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既有适合小白学习的零基础资料，也有适合3年以上经验的小伙伴深入学习提升的进阶课程，涵盖了95%以上Go语言开发知识点，真正体系化！

由于文件比较多，这里只是将部分目录截图出来，全套包含大厂面经、学习笔记、源码讲义、实战项目、大纲路线、讲解视频，并且后续会持续更新

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;
	a <<= 1;
	b >>= 1;

	flag = ((b & 1) > 0) && (ans += a) > 0;

	return ans >> 1;
}
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}

int sumNums(int n){
// 2的14次正好超过10000
// 等差数列求和公式n * (n + 1) / 2
int ans = 0, a = n, b = n + 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);
a <<= 1;
b >>= 1;

(b & 1) && (ans += a);

return ans >> 1;
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}




---


### c++



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class Solution {
public:
int sumNums(int n) {
// 2的14次正好超过10000
// 等差数列求和公式n * (n + 1) / 2
int ans = 0, a = n, b = n + 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);
    a <<= 1;
    b >>= 1;

    (b & 1) && (ans += a);

    return ans >> 1;
}
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};




---


### python



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class Solution:
def sumNums(self, n: int) -> int:
# 2的14次正好超过10000
# 等差数列求和公式n * (n + 1) / 2
ans = 0
a = n
b = n + 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)
    a <<= 1
    b >>= 1

    (b & 1) and (ans := ans + a)

    return ans >> 1
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---


### go



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func sumNums(n int) int {
// 2的14次正好超过10000
// 等差数列求和公式n * (n + 1) / 2
ans, a, b := 0, n, n + 1
addGreatZero := func() bool {
ans += a
return ans > 0
}

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()
a <<= 1
b >>= 1

\_ = ((b & 1) > 0) && addGreatZero()

return ans >> 1
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}




---


### rust




![img](https://img-blog.csdnimg.cn/img_convert/066a527707e5ee0ab9d75eb7ee3811c3.png)
![img](https://img-blog.csdnimg.cn/img_convert/d9e0cba55a71acb7206153ac9744dd8a.png)
![img](https://img-blog.csdnimg.cn/img_convert/e3a4321a19eb8d42c02035300f0741d3.png)

**既有适合小白学习的零基础资料，也有适合3年以上经验的小伙伴深入学习提升的进阶课程，涵盖了95%以上Go语言开发知识点，真正体系化！**

**由于文件比较多，这里只是将部分目录截图出来，全套包含大厂面经、学习笔记、源码讲义、实战项目、大纲路线、讲解视频，并且后续会持续更新**

**[如果你需要这些资料，可以戳这里获取](https://bbs.csdn.net/topics/618658159)**



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rust

[外链图片转存中…(img-2NTezSwg-1715484856276)]
[外链图片转存中…(img-AsHG4FRA-1715484856276)]
[外链图片转存中…(img-Gb24AuZ1-1715484856276)]

既有适合小白学习的零基础资料，也有适合3年以上经验的小伙伴深入学习提升的进阶课程，涵盖了95%以上Go语言开发知识点，真正体系化！

由于文件比较多，这里只是将部分目录截图出来，全套包含大厂面经、学习笔记、源码讲义、实战项目、大纲路线、讲解视频，并且后续会持续更新

如果你需要这些资料，可以戳这里获取

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