在项目里我们一般都会把自己第一次提交的配置文件忽略本地跟踪
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[Sun@webserver2 demo]$ git update-index --assume-unchanged <filename>
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但是项目里的其他人如果不小心把该配置文件修改push到远程仓库之后，我们git pull代码的时候就会报错
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[Sun@webserver2 demo]$ git add .
[Sun@webserver2 demo]$ git commit -m
'update:index.php'
[master f8a7428] update:index.php
1
file
changed, 1 insertion(+), 1 deletion(-)
[Sun@webserver2 demo]$ git pull
remote: Counting objects: 5,
done
.
remote: Compressing objects: 100% (2
/2
),
done
.
remote: Total 3 (delta 1), reused 0 (delta 0)
Unpacking objects: 100% (3
/3
),
done
.
From git.oschina.net:sunzmit
/thinkphp
1bc9485..c63dff3 master -> origin
/master
error: Your
local
changes to the following files would be overwritten by merge:
config.ini
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大意是：您的本地更改的文件将被合并覆盖。并指出了会被覆盖的文件
解决方法：
1.撤销本地对文件的忽略
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[Sun@webserver2 demo]$ git update-index --no-assume-unchanged config.ini
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2.从最近的一次提交中读取内容，备份当前的工作区的内容，将当前的工作区内容保存到Git栈中
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[Sun@webserver2 demo]$ git stash
Saved working directory and index state WIP on master: f8a7428 update:index.php
HEAD is now at f8a7428 update:index.php
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3.pull远程仓库代码
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[Sun@webserver2 demo]$ git pull
Merge made by the
'recursive'
strategy.
config.ini | 2 +-
1
file
changed, 1 insertion(+), 1 deletion(-)
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4.从Git栈中读取最近一次保存的内容，恢复工作区的相关内容
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[Sun@webserver2 demo]$ git stash pop
Auto-merging config.ini
CONFLICT (content): Merge conflict
in
config.ini
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5.修改合并
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[Sun@webserver2 demo]$ vim config.ini
<<<<<<< Updated upstream
This is a
test
file
!!!!!!!!!!!!!!!!
=======
This is a
test
file
>>>>>>> Stashed changes
[Sun@webserver2 demo]$
cat
test
.txt
This is a
test
file
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<<<<<<< Updated upstream到=======中是从远程仓库pull下来别人的内容，=======到>>>>>>> Stashed changes中是我们本地文件内容，现在我们可以删除其他，只保留自己的内容This is a test file
6.把文件回复到最新提交的版本，会保留修改内容
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[Sun@webserver2 demo]$ git reset HEAD config.ini
Unstaged changes after reset:
M config.ini
[Sun@webserver2 demo]$
cat
test
.txt
This is a
test
file
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7.再次忽略本地跟踪，完成！
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[Sun@webserver2 demo]$ git update-index --assume-unchanged config.ini
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8.最后不要忘记清除Git栈的备份
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[Sun@webserver2 demo]$ git stash drop
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