Python fabric 1.4 解决run() received nonzero return code 2 while executing出错后脚本不能继续执行故障_python non-zero return code

默认情况下fabric配置参数warn_only=False，即run指令得到的程序结束返回值不为0则引发异常，退出后续的部署。

参考一下代码，有两种方式设置warn_only=True，可实现出错后能继续向下执行

def deploy():
    with settings(
            warn_only=True
    ):
        run("ls /zz| grep ccc| grep -v fdsfds")
    print "111"
    run("ls /zz", warn_only=True)
    print "222"

输出参考

D:\code\devops\trunk>fab -f test.py deploy
[] Executing task 'deploy'
[127.0.0.1:22] run: ls /zz| grep ccc| grep -v fdsfds
[127.0.0.1:22] out: ls: cannot access /zz: No such file or directory
[127.0.0.1:22] out:
 
 
Warning: run() received nonzero return code 1 while executing 'ls /zz| grep ccc| grep -v fdsfds'!
 
111
[127.0.0.1:22] run: ls /zz
[127.0.0.1:22] out: ls: cannot access /zz: No such file or directory
[127.0.0.1:22] out:
 
 
Warning: run() received nonzero return code 2 while executing 'ls /zz'!
 
222
 
Done.
Disconnecting from 127.0.0.1:22... done.